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marta [7]
3 years ago
8

How many molecules of NaOH are in 23 moles of NaOH

Chemistry
1 answer:
Ann [662]3 years ago
3 0
120 grams of NaOH means 3 Moles of NaOH because 40 grams (Molecular Weight in grams) is one mole of NaOH.

Each mole of any substance contain Avogadro’s number of molecules ie., 6.022 x (10 to the power 23).

Hence 3 Moles of NaOH contain 3 times of Avogadro’s number of molecules ie., 3 x 6.022 x (10 to the power 23)
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What is the last energy level of N? Mg?
Alexandra [31]

Answer:

2

3

Explanation:

To infer the last energy of the given atoms, we need to write their electronic configuration:

For N = 1S² 2S² 2P³

     Mg  = 1S² 2S² 2P⁶ 3S²  

The energy levels are usually designated as;

   n = 1

   n = 2

   n = 3

   n =4

For N, the last energy level is 2

     Mg, the last energy level is 3

We can also determine this number by the periods the atoms can be found.

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3 years ago
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GarryVolchara [31]

Answer:

76.9L

Explanation:

Based on the graph, whenever the temperature increases by 100K, the volume increases by 10L, so do 769/10

7 0
2 years ago
How many grams would you have if you had 2.478 moles of Calcium Phosphate? (SHOW ALL WORK FOR BRAINLIEST)
saul85 [17]

Answer:u would have 40

Explanation:

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Which of the following reactions would be predicted by the activity series list
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Answer:

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Read 2 more answers
Given the following unbalanced equation:
antiseptic1488 [7]
<h3>Answer:</h3>

11.84 mol CoF₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis
  • Analyzing Reactions RxN
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] CoCl₂ + F₂ → CoF₂ + Cl₂

[RxN - Balanced] CoCl₂ + F₂ → CoF₂ + Cl₂

[Given] 11.84 moles CoCl₂

[Solve] moles CoF₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol CoCl₂ → 1 mol CoF₂

<u>Step 3: Stoich</u>

  1. [DA] Set up:                                                                                                       \displaystyle 11.84 \ mol \ CoCl_2(\frac{1 \ mol \ CoF_2}{1 \ mol \ CoCl_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                          \displaystyle 11.84 \ mol \ CoF_2
7 0
3 years ago
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