PLEASE HELP ASAP......!!!!!!

Mathematics

1 answer:

Musya8 [376]2 years ago

7 0

Answer:

If you roll two dices, you can get as results all numbers from 2 to 12. Among these, the prime numbers are 2, 3, 5, 7, 11. The probability you get each of them is: 2: you can get it only as 1+1, so one combination over 36 possibility. Probability: 1/36. 3: you can get it as 1+2 or 2+1, so two combinations over 36 possibility. Probability: 2/36. 5: you can get it as 1+4, 2+3, 3+2, 4+1, so four combinations over 36 possibility. Probability: 4/36. 7: you can get as 1+6, 2+5, 3+4, 4+3, 5+2, 6+1, so six combinations over 36 possibility. Probability: 6/36. 11: you can get it as 5+6 or 6+5 so two combinations over 36 possibility. Probability: 2/36. The total probability of getting a prime number is the sum of the probabilities, which is 15/36. So m=15, n=36 and 10m+n=150+36=186.

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VLD [36.1K]

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i think thats how you would solve it
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4 0

3 years ago

Find the value of $x$ so that the ratios are equivalent. x:5/2 and 8:10

Scrat [10]

Answer:

x=2

Step-by-step explanation:

Here what we need is that the ratios be equal, which is:

x:(5/2) = 8:10 or, what is the same:

x/(5/2) = 8/10

Lets pick the left term x/(5/2) and multiply both numerator and denominator by 2 to eliminate the fraction on the denominator:

2x/2(5/2) = 2x/5

Now, we would like to make a 10 appear on the denominator. As we already have a five we need to multiply numerator and denominator by the num that, multiplied by 5 gives as 10, this is 2:

2(2x)/2(5) = 4x / 10

So, we transformed x/(5/2) in 4x/10, and both are the same, so we can replace it on our first equation:

4x/10 = 8/10

As both denominators are equal, we can concentrate only in numerators:

4x = 8

Dividing both sides by 4:

x = 2

So, for x=2 both ratios are equivalents.

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3 years ago

This year, 1,272 students enrolled in night courses a a local college. Last year only 1,200 students enrolled. What was the perc

Ahat [919]

The percent increase in enrollment is 6 %

The operation used in first step is finding the difference between final value and initial value

<h3>Solution:</h3>

Given that This year, 1,272 students enrolled in night courses a a local college

Last year only 1,200 students enrolled.

To find: percent increase in the enrollment

The percent increase between two values is the difference between a final value and an initial value, expressed as a percentage of the initial value.

The percent increase is given as:

$\text { percentage increase }=\frac{\text { final value - initial value}}{\text { initial value }} \times 100$

Here initial value (last year) = 1200 and final value(this year) = 1272

Substituting the values in above formula,

$\begin{aligned}&\text { percentage increase }=\frac{1272-1200}{1200} \times 100\\\\&\text { percentage increase }=\frac{72}{1200} \times 100=6\end{aligned}$