First, we need to work out the total number of students who were being surveyed.
We know that half of the students has two pets. The rest of the students make up the other half. So, we have 3 students + 2 students + 8 students = 13 students that make half of the sample population
That means total number of students being surveyed is 13+13=26 students
Then we work out the probability
P(One pet) = 8/26 = 4/13
P(Two pets) = 1/2
P(Three pets) = 3/26
P( Four pets) = 2/26 = 1/13
The probability distribution is shown in the table below. Let

be the number of pets and

is the probability of owning the number of pets
1/3 of remained 2/3 is 2/9. We’ve used 1/3+2/9 = 3/9+2/9 = 5/9. So we’ve used 5/9 and we have 4/9 of the paint
Fairly straightforward question. She works 30 days and is late 80% or 0.8
We can model our equation
Num days late = late percentage * num working days
Basically fine portion of working days that she was late.
Num days late = 0.8 * 30=24
So Deborah was late 24 out of 30 working days. Would appreciate a brainliest
Answer:
$6250
Step-by-step explanation:
5000 = 80%
5000/80=62.5
62.5*100=6250
Answer:
x=4
y=1
Step-by-step explanation:
4x=7y+9
4x+y=17
7y+9+y=17
8y=17-9
8y=8
y=1
so
4x=7*1+9
4x=16
x=16/4
x=4