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vitfil [10]
2 years ago
11

What is the concentration of kl solution if 20.68g of solute was added to enough water to form 100ml solution?

Chemistry
1 answer:
rewona [7]2 years ago
5 0

Answer:

1.25 M

Explanation:

Step 1: Given data

Mass of KI (solute): 20.68 g

Volume of the solution: 100 mL (0.100 L)

Step 2: Calculate the moles of solute

The molar mass of KI is 166.00 g/mol.

20.68 g × 1 mol/166.00 g = 0.1246 mol

Step 3: Calculate the molar concentration of KI

Molarity is equal to the moles of solute divided by the liters of solution.

M = 0.1246 mol/0.100 L= 1.25 M

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pishuonlain [190]
3.07g H2

27.4/26.98/2x3x1.01x2=3.07
6 0
3 years ago
How do I solve this? please help and only respond with the answer/work. I will mark BRAINLIEST
Ulleksa [173]

Answer: I think the answer is 2.5 M.

Explanation:  Formula: M = n/v

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4 0
2 years ago
What are the parts of the water system? Label the water wheel to show the matter and forms energy that flow through the system.
Irina-Kira [14]

Answer:

Source, processing and distribution are the components of water system.

Explanation:

There are three parts of water system i. e. the source, the processing and distribution. Water is extracted from a source such as underground water, lake or river etc. After extraction this water is transported to the processing unit where it can be purified and after purification it is distributed to all places where it is needed. Potential energy is a form of energy that flows through this water system because the water is extracted from a depth and we know that depth and height refers to potential energy.

8 0
3 years ago
Given the balanced equation below, calculate the moles of aluminum that are needed to react completely with 28.7 moles of FeO. Y
Alexxx [7]

Answer:

43.05 moles of Al needed to react with 28.7 moles of FeO.

Explanation:

Given data:

Moles of FeO = 28.7 mol

Moles of Al needed to react with FeO = ?

Solution:

Chemical equation:

2Al + 3FeO → 3Fe + Al₂O₃

Now we will compare the moles of Al with FeO.

                            FeO        :           Al

                             2            :            3

                          28.7          :         3/2×28.7 = 43.05 mol

Thus 43.05 moles of Al needed to react with 28.7 moles of FeO.

8 0
3 years ago
An object has a mass of 55 grams and a density of 3.23g/ml ? what is the volume
lara [203]
Volume= mass divided by density
V= m/d
55/3.23
= 17.03
8 0
2 years ago
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