AgNO3 reacts with CoCl2 based on the following equation:
<span>AgNO3 + CoCl2 ........> CoNO3 + AgCl<span>2
</span></span>
The complete ionic equation for this reaction is:
<span>Co2+(aq) + 2Cl- (aq) + 2Ag+(aq) + 2NO3-(aq) ...> 2AgCl(s) + Co2+(aq) + 2NO3-(aq)
</span>while the net ionic equation is:
<span>Cl-(aq) + Ag+(aq) → AgCl(s)
</span>
From this ionic equations, we can see that Co2+ and NO3- remained unchanged in the ionic equations. Therefore <span>Co2+ and NO3- are the spectator ions.</span>
Answer:
A) 900 J
B) 27.96 J
C) 1,628 J ≅ 1.63 kJ
Explanation:
The heat absorbed by the metal (silver) - or energy required to heat it - is calculated as:
heat = mass x Cp x ΔT
Where Cp is the heat capacity (0.24 J/°C ·g) and ΔT is the change in temperature (final T - initial T).
A) Given:
mass = 150.0 g
final T = 298 K = 25°C
initial T = 273 K = 0°C
We calculate the energy in J to raise the temperature:
heat = mass x Cp x (final T - initial T)
= 150 .0 g x 0.24 J/°C ·g x (25°C - 0°C )
= 900 J
B) Given:
moles Ag= 1.0 mol
ΔT = 1.08°C
We first calculate the mass of silver (Ag) by multiplying the moles of Ag by the molar mass of Ag (MM = 107.9 g/mol)
mass = moles x MM = 1.0 mol Ag x 107.9 g/mol Ag = 107.9 g
Then, we calculate the heat required:
heat = mass x Cp x ΔT = 107.9 g x 0.24 J/°C ·g x 1.08°C = 27.96 J
C) Given:
heat = 1.25 kJ = 1,250 J
final T = 15.28°C
initial T = 12.08°C
We first calculate the change in temperature:
ΔT = final T - initial T = 15.28°C - 12.08°C = 3.2°C
Then, we calculate the mass of silver:
mass = heat/(Cp x ΔT) = 1,250 J/(0.24 J/°C ·g x 3.2°C) = 1,628 J ≅ 1.63 kJ
Answer: A, Nucleus
B, Cell memebrane
C, vacuole
D, Chloroplast, mitocondria, amyloplast.
Explanation:
These only work if this is a plant cell which you did not specify.
The information given in the question is not enough to determine the acidity of the solution. This is because, acidity can only be found with the equation: pH = -log [H+].
In order to determine the acidity of the solution, the half titration point value is needed, this will make it possible to determine the value of H30+. If the half point titration value is known, then Ka will be equivalent to pH and the value will be evaluated using the equation: - log (1.6 * 10^-10).
Answer:
A
Explanation:
because it loses 2 electrons
