Answer:
Step-by-step explanation:
From the given information:
r = 10 cos( θ)
r = 5
We are to find the the area of the region that lies inside the first curve and outside the second curve.
The first thing we need to do is to determine the intersection of the points in these two curves.
To do that :
let equate the two parameters together
So;
10 cos( θ) = 5
cos( θ) = 
Now, the area of the region that lies inside the first curve and outside the second curve can be determined by finding the integral . i.e
The diagrammatic expression showing the area of the region that lies inside the first curve and outside the second curve can be seen in the attached file below.
Answer:
40.2%
Step-by-step explanation:
(New-old)/old
(3750.25-2675.25)/2675.25=0.4018
0.4018×100= 40.2%
Answer:
y - 9 = -6( x - 0)
y - 9 = -6x + 0
y = -6x + 9
Step-by-step explanation:
Step-by-step explanation:
7(2x+5)=11x-9-x
14x+35=10x-9
4x+35=-9
4x=-44
x=-11
Answer:
852
6×10(6)+7×10(5)+3×10(2)+8×10+2= 852
Step-by-step explanation:
ORDER OF OPERATIONS Will really help you solve this long problem.
Order of operations is PEMDAS.
P-parenthesis
E-exponents
M-multiplication
D-division
A-addition
S-subtraction
6)(10)(6)+(7)(10)(5)+(3)(10)(2)+(8)(10)+2
=(60)(6)+(7)(10)(5)+(3)(10)(2)+(8)(10)+2
=360+(7)(10)(5)+(3)(10)(2)+(8)(10)+2
=360+(70)(5)+(3)(10)(2)+(8)(10)+2
=360+350+(3)(10)(2)+(8)(10)+2
=710+(3)(10)(2)+(8)(10)+2
=710+(30)(2)+(8)(10)+2
=710+60+(8)(10)+2
=770+(8)(10)+2
=770+80+2
=850+2
=852
