There are 4 questions related to this problem:
1 If the half-life of the drug is 7.3 hours, what fraction of the drug remains in the patient after 24 hours?The amount of the drug is halved every 7.3-hour period, and 24 hours equals 24/7.3 of these halving periods.
So the portion of the drug left over after 24 hours is (1/2) ^ (24/7.3) = 0.10224 2 Write a general expression for the amount of the drug in the patient immediately after taking the nth dose of the drug
One method is to combine the residual amounts from each amount, when the nth dose arises; this will contain adding a finite geometric series
So the total amount of the drug immediately after the nth dose, in mg, is An = 40+ 40(0.10224) + 40(0.10224)^2 + ... + 40(0.10244)^(n-1)
An = 40[1 - (0.010224)^n]/(1 - 0.10224)
3 Write a broad expression for the quantity of the drug in the patient directly before taking the nth dose of the drug
Pn = An – 40
= 40(0.10224) + 40(0.10224)^2 + ... + 40(0.10244)^(n-1)
= 40(0.10224) [1 - (0.10224)^(n-1)]/(1 – 0.10224)
= 4.0895 [1 - (0.10224)^(n-1)]
4 What is the long-term minimum amount of drug in the patient?
= lim n-->infinity of Pn
= lim n-->infinity of 4.0895[1 - (0.10224)^(n-1)]
= 4.0895(1 - 0)
= 4.0895 mg.
Answer:
Explanation:
y_1 = (3 mm) sin(x - 3t)
comparing it with standard wave equation
y = A sin( ωt-kx )
we see
ω = -3 , k = -1
velocity = ω / k
= 3
y_2 = (6 mm) sin(2x - t)
we see
ω = -1 , k = -2
velocity = ω / k
= .5
y_3 = (1 mm) sin(4x - t)
we see
ω = -1 , k = -4
velocity = ω / k
= .25
y_4 = (2 mm) sin(x - 2t)
we see
ω = -2 , k = -1
velocity = ω / k
= 2
So greatest velocity to lowest velocity
y_1 = (3 mm) sin(x - 3t) , y_4 = (2 mm) sin(x - 2t) ,y_2 = (6 mm) sin(2x - t) , y_3 = (1 mm) sin(4x - t)
b )
Given the mass per unit length of wire the same , velocity is proportional to
√ T , where T is tension
so in respect of tension in the wire same order will exist for highest to lowest tension .
The height, h to which the package of mass m bounces to depends on its initial velocity, v and the acceleration due to gravity, g and is given below:
<h3>What are perfectly elastic collision?</h3>
Perfectly elastic collisions are collisions in which the momentum as well as the energy of the colliding bodies is conserved.
In perfectly elastic collisions, the sum of momentum before collision is equal to the momentum after collision.
Also, the sum of kinetic energy before collision is equal to the sum of kinetic energy after collision.
Since some of the Kinetic energy is converted to potential energy of the body;
Therefore, the height to which the package m bounces to depends on its initial velocity and the acceleration due to gravity.
Learn more about elastic collisions at: brainly.com/question/7694106
The hierarchy of need was developed by Maslow. The pyramid is a motivational theory in psychology that argues that people is seeking to meet successively higher needs. The base of the pyramid is for the physiological needs to safety, belongingness, esteem, and finaly self-actualization.
Answer:
Explanation:
Given
Initial velocity of first billiard ball 
Initial velocity of second billiard ball 
After collision first ball comes to rest
suppose m is the mass of both the balls
Conserving momentum to get the speed of second ball after collision
Initial momentum 
Final momentum 
where 
and 
are the speed of first and second ball respectively
thus speed of second ball after collision is equal to speed of first ball before collision
