Question

A billiard ball traveling at 3.4 m/s has an elastic head-on collision with a billiard ball of equal mass that is initially at rest. The first ball is at rest after the collision. What is the speed of the second ball after the collision?

Answer 1

Answer:

Explanation:

Given

Initial velocity of first billiard ball $u_1=3.4\ m/s$

Initial velocity of second billiard ball $u_2=0\ m/s$

After collision first ball comes to rest

suppose m is the mass of both the balls

Conserving momentum to get the speed of second ball after collision

Initial momentum $P_i=mu_1+mu_2=m\cdot 3.4+0$

Final momentum $P_f=mv_1+mv_2$

where $v_1$ and $v_2$ are the speed of first and second ball respectively

$P_i=P_f$

$m\cdot 3.4+0=0+m\cdot v_2$

$v_2=3.4\ m/s$

thus speed of second ball after collision is equal to speed of first ball before collision

Answer 2

Answer:

Explanation:

Just put the answer