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ankoles [38]
3 years ago
11

A billiard ball traveling at 3.4 m/s has an elastic head-on collision with a billiard ball of equal mass that is initially at re

st. The first ball is at rest after the collision. What is the speed of the second ball after the collision?
Physics
2 answers:
Tpy6a [65]3 years ago
3 0

Answer:

Explanation:

Given

Initial velocity of first billiard ball u_1=3.4\ m/s

Initial velocity of second billiard ball u_2=0\ m/s

After collision first ball comes to rest

suppose m is the mass of both the balls

Conserving momentum to get the speed of second ball after collision

Initial momentum P_i=mu_1+mu_2=m\cdot 3.4+0

Final momentum P_f=mv_1+mv_2

where v_1 and v_2 are the speed of first and second ball respectively

P_i=P_f

m\cdot 3.4+0=0+m\cdot v_2

v_2=3.4\ m/s

thus speed of second ball after collision is equal to speed of first ball before collision

Artemon [7]3 years ago
3 0

Answer:

Explanation:

Just put the answer

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