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13.06m
Explanation:
Given parameters:
initial velocity u = 0
final velocity v = 16m/s
Unknown;
height of the hill = ?
Solution:
We are going to apply one of the laws of motion to solve this problem;
V² = U² + 2gH
where V is the final velocity
U is the initial velocity
g is the acceleration due to gravity = 9.8m/s²
H is the height
since initial velocity is zero;
V² = 2gH
To find the height;
H = 
H =
= 13.06m
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Answer:

Explanation:
As we know that base of the slab is given as


now we know that rate of heat transfer is given as

here we know that

Also we have



Answer:
185 N
Explanation:
Sum of forces in the x direction:
Fₓ = -(80 N cos 75°) + (120 N cos 60°)
Fₓ = 39.3 N
Sum of forces in the y direction:
Fᵧ = (80 N sin 75°) + (120 N sin 60°)
Fᵧ = 181.2 N
The magnitude of the net force is:
F = √(Fₓ² + Fᵧ²)
F = √((39.3 N)² + (181.2 N)²)
F = 185 N
Answer:
V = 6 m/s
Explanation:
Given that,
Initial speed of an object is 20 m/s
Final speed of an object is 10 m/s
Time, t = 5 s
We need to find the average speed of the object during these 5 seconds. Let it is equal to V. Here, time is same. The average speed is given by :

So, the average speed of the object is 6 m/s.