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aliya0001 [1]
2 years ago
12

If a cannonball is fired horizontally it will not go in a straight line why?

Physics
1 answer:
goldfiish [28.3K]2 years ago
5 0

Explanation:

A projectile (Cannon ball) is launched at an angle to the horizontal and rises up to a peak while moving horizontally. When it reaches the peak, the projectile starts to fall.

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A classroom is about 3 meters high, 20 meters wide and 30 meters long. If the density of air is 1.29 kg/m3, what is the mass of
Deffense [45]

Answer:

the mass of the air in the classroom = 2322 kg

Explanation:

given:

A classroom is about 3 meters high, 20 meters wide and 30 meters long.

If the density of air is 1.29 kg/m3

find:

what is the mass of the air in the classroom?

density = mass / volume

where mass (m) = 1.29 kg/m³

volume = 3m x 20m x 30m = 1800 m³

plugin values into the formula

  1.29 kg/m³   =  <u>      mass    </u>

                             1800 m³

mass =  1.29 kg/m³  ( 1800 m³ )

mass = 2322 kg

therefore,

the mass of the air in the classroom = 2322 kg

8 0
3 years ago
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Explain the relationship between mass volume and density
IrinaK [193]
Mass is a body of matter of indefinite shape and considerable size. Density is the degree to which something is filled.  Check this website for more a better understanding : <span>www.answers.com/Q/What_is_the_relationship_between_density_and_volume</span>
8 0
3 years ago
When light encounters a barrier with slits cut it in it, the light will bend through the slits creating a pattern like that seen
lawyer [7]

Answer:

reflection

Explanation:

an example would be looking in the mirror

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3 years ago
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What would happen to the function or purpose of flower if the stigma wasn't sticky?
sashaice [31]

Answer:

The plant would not reproduce because the flower uses the stigma to catch the pollen

8 0
2 years ago
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The intensity of the Sun's light in the vicinity of the Earth is about 1000W/m^2. Imagine a spacecraft with a mirrored square sa
NeX [460]

Explanation:

Formula to represent thrust is as follows.

             F = \frac{dP}{dt}

                = \frac{2p}{dt}

or,           p = \frac{E}{c}

         \frac{p}{dt} = \frac{W}{c}

                  F = \frac{2IA}{c}

                     = \frac{2 (1000 W/m^{2})(5.5 \times 10^{3} m)^{2}}{3 \times 10^{8} m/s}

                     = 201.67 N

Thus, we can conclude that the thrust is 201.67 N.

8 0
3 years ago
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