Guys do anybody know the answer to this????????????????
1 answer:
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Let . The gradient of
at the point (1, 0, 0) is the normal vector to the surface, which is also orthogonal to the tangent plane at this point.
So the tangent plane has equation
Compute the gradient:
Evaluate the gradient at the given point:
Then the equation of the tangent plane is
Answer:
Two positive zeros, no negative zeros, two complex roots.
Step-by-step explanation:
The given function is
According to the fundamental theorem of algebra, the function will have 4 roots.
The graph of the function intersects the positive axis at two points.
Hence the function has two positive zeros and no negative zeros.
The two remaining roots are imaginary. The function has two complex zeros.
See graph in attachment
