Guys do anybody know the answer to this????????????????
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Neither the <u>laws of sines</u> nor the <u>law of cosines</u> can be used to solve the triangle. The correct option is the third option - neither law can be used
<h3>Solving trianngles using the laws of sines & cosines </h3>The law of sines is written as
Where a,b, and c are sides of any given triangle and A,B, and C are the angles.
This law is used when we are given either
- Two angles and one side, or
- Two sides and a non-included angle
The law of cosines is written as
a² = b² + c² -2bc cosA, or
b² = a² + c² - 2ac cosB, or
c² = a² + b² -2ab cosC
Where a,b, and c are sides of any given triangle and A,B, and C are the angles.
This law is used when we are given either
- Three sides or
- Two sides and the included angle
Now, for triangle xyz, which the measures of angles X,Y, and Z are known, neither law can be used to solve the triangle.
Hence, neither the <u>laws of sines</u> nor the <u>law of cosines</u> can be used to solve the triangle. The correct option is the third option - neither law can be used
Learn more on Solving triangles using the laws of sines & cosines here: brainly.com/question/22339733