The answer is 23 and 1÷9
First you multiply 4 by 5 and wind up with 20
Then you multiply four by 7÷9.
That gets you 28÷9
You take out all the nines you can from 28, three in this case.
That gets you 27÷9 + 1÷9
Your total thing is 20+27÷9+1÷9
That equals 20+3+1÷9
That equals 23 and 1÷9
Answer:
740
Step-by-step explanation:
The n th term of an arithmetic series is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given a₃ = 7 and a₇ = (3 × 7) + 2 = 21 + 2 = 23 , then
a₁ + 2d = 7 → (1)
a₁ + 6d = 23 → (2)
Subtract (1) from (2) term by term
4d = 16 ( divide both sides by 4 )
d = 4
Substitute d = 4 into (1)
a₁ + 2(4) = 7
a₁ + 8 = 7 ( subtract 8 from both sides )
a₁ = - 1
The sum to n terms of an arithmetic series is
= 
[ 2a₁ + (n - 1)d ] , thus
= 
[ (2 × - 1) + (19 × 4) ]
= 10(- 2 + 76) = 10 × 74 = 740
Answer:
Step-by-step explanation:
they want to know the high and low quiz scores... that's all
Hey! :)
10y-3(y+5)
Distribute the -3.
-3*y= -3y -3*5= -15
10y-3y-15
7y-15
"A" is the answer.
~'Manda
It really depends on what kind of problem. like if you are doing a word problem or whatever than you should read the question a couple times, underline key words, DECIDE which operation to use, refer to the question and see if it makes sense. Hope I helped :)
