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Aleksandr-060686 [28]
3 years ago
6

Which scientist was the first to propose that atomic structure contains electrons?

Chemistry
1 answer:
Snezhnost [94]3 years ago
3 0
Answer: J.J. Thompson
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A sample of an unknown liquid has a volume of 30.0 mL and a mass of 6 g. What is its density? i need this hella quick
Lana71 [14]

density= mass/volume

density= 6g/30.0 ml

density= 0,2 g/ml

7 0
3 years ago
Here anwser questions 2 ,4,6 those charts okay I also put how the formula on top solve these problems ! Please help me I geniunu
disa [49]

Answer:

39.5L

Explanation:

4 0
3 years ago
What is the force that opposes the sliding motion of two touching surfaces?
Advocard [28]

Answer: The force that acts against your pushing force is called friction. is a force that resists the motion between two surfaces in contact. When you try to slide two surfaces across each other, the force of friction resists the sliding motion.

3 0
3 years ago
54.0g Al reacts with 64.0g O2 to form Al2O3 according to the equation.
pentagon [3]

Answer:

136 g Al₂O₃

Explanation:

Assuming you do not need to find the limiting reactant, to find the mass of Al₂O₃, you need to (1) convert grams O₂ to moles O₂ (via molar mass), then (2) convert moles O₂ to moles Al₂O₃ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles Al₂O₃ to grams Al₂O₃ (via molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (64.0 g).

Molar Mass (O₂): 32 g/mol

Molar Mass (Al₂O₃): 102 g/mol

4 Al + 3 O₂ -----> 2 Al₂O₃

64.0 g O₂           1 mole           2 moles Al₂O₃            102 g
-----------------  x  --------------  x  ------------------------  x   -------------  =  136 g Al₂O₃
                             32 g               3 moles O₂             1 mole

6 0
2 years ago
Read 2 more answers
In a room full of air, the air is mainly composed of Nitrogen and Oxygen molecules (both at room temperature). Find (to two sign
zloy xaker [14]

Explanation:

Expression for the v_{rms} speed is as follows.

            v_{rms} = \sqrt{\frac{3kT}{M}}

where,   v_{rms} = root mean square speed

                     k = Boltzmann constant

                    T = temperature

                    M = molecular mass

As the molecular weight of oxygen is 0.031 kg/mol and R = 8.314 J/mol K. Hence, we will calculate the value of v_{rms} as follows.

               v_{rms} = \sqrt{\frac{3kT}{M}}

                            = \sqrt{\frac{3 \times 8.314 J/mol K \times 309.02 K}{0.031 kg/mol}}

                            = 498.5 m/s

Hence, v_{rms} for oxygen atom is 498.5 m/s.

For nitrogen atom, the molecular weight is 0.028 kg/mol. Hence, we will calculate its v_{rms} speed as follows.

                v_{rms} = \sqrt{\frac{3kT}{M}}

                              = \sqrt{\frac{3 \times 8.314 J/mol K \times 309.92 K}{0.028 kg/mol}}

                              = 524.5 m/s

Therefore, v_{rms} speed for nitrogen is 524.5 m/s.

3 0
3 years ago
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