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marin [14]
2 years ago
15

Simplify - Factor a

Chemistry
1 answer:
Dmitriy789 [7]2 years ago
7 0

Answer:

Option 1

Explanation:

Option number 1 is the most compact one which indicates it is a solid

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What major product is formed when heptyne is treated with Br2 in CCl4?
ANTONII [103]

Answer:A 1,2-dibromoheptene

Explanation:

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3 years ago
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What is the lowest unoccupied molecular orbital in F2?
Juliette [100K]

Answer:

σ*2pₓ, also called 3\sigma_{u}\text{*}

Explanation:

I have drawn the MO diagram for fluorine below.

Each F atom contributes seven valence electrons, so we fill the MOs of fluorine with 14 electrons.

We have filled the \pi \text{*2p}_{y} and \pi \text{*2p}_{z} MOs.

They are the highest occupied molecular orbitals (HOMOs).

The next unfilled level (the LUMO) is the σ*2pₓ orbital. If you use the symmetry notation, it is called the 3\sigma_{u}\text{*} orbital.

This is the orbital that fluorine uses when it acts as an electron acceptor.

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3 years ago
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Setler [38]
The answer would be 3 cm. you round down to the nearest whole number when it is less than 5. you round up when it is 5 or more.
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2 years ago
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A 7.337 gram sample of chromium is heated in the presence of excess oxygen. A metal oxide is formed with a mass of 9.595 g. Dete
Thepotemich [5.8K]
<h3>Answer:</h3>

Empirical formula is CrO

<h3>Explanation:</h3>

<u>We are given;</u>

  • Mass of sample of Chromium as 7.337 gram
  • Mass of the metal oxide formed as 9.595 g

We are required to determine the empirical formula of the metal oxide.

<h3>Step 1 ; Determine the mass of oxygen used </h3>

Mass of oxygen = Mass of the metal oxide - mass of the metal

                          = 9.595 g - 7.337 g

                         = 2.258 g

<h3>Step 2: Determine the moles of chromium and oxygen</h3>

Moles of chromium metal

Molar mass of chromium = 51.996 g/mol

Moles of Chromium = 7.337 g ÷ 51.996 g/mol

                                 = 0.141 moles

Moles of oxygen

Molar mass of oxygen = 16.0 g/mol

Moles of Oxygen = 2.258 g ÷ 16.0 g/mol

                            = 0.141 moles

<h3>Step 3: Determine the simplest mole number ratio of Chromium to Oxygen</h3>

Mole ratio of Chromium to Oxygen

          Cr : O

0.141 mol : 0.141 mol

             1 : 1

Empirical formula is the simplest whole number ratio of elements in a compound.

Thus the empirical formula of the metal oxide is CrO

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The better era tbh.......
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