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3 years ago

What are the sign and magnitude of the charge of atom containing 14 protons, 15 neutrons, and 12 electrons?

1 answer:

7 0

<span>We know that protons gives positive charge, neutrons no charge and electrons negative, then +14 - 12 = +2 So the charge of the atom is sign positive and magnitude 2</span>

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The top of the syringe is a circle. You need to

AfilCa [17]

Answer:10.2 cm2

Explanation:

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3 years ago

PLEASE HELP What's the mass in grams of 0.442 moles of calcium bromide, CaBr2? The atomic

djverab [1.8K]

Answer: Thus there are 88.4 g of calcium bromide.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

Molar mass of = 40.1 (1)+ 2(79.9) = 199.9

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$0.442=\frac{x}{199.9}$

$x=88.4g$

Thus there are 88.4 g of calcium bromide.

7 0

2 years ago

Indicates the kind, number, arrangement, and bonds but not the unshared pairs of the atoms in a molecule.

Vikki [24]

Electronic configuration

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2 years ago

A sample of octane undergoes combustion according to the equation 2 C8H18 + 25 O2 → 16 CO2 + 18 H2O ΔH°rxn = -11018 kJ. What mas

Anna71 [15]

Answer:

$\large \boxed{\text{528.7 g} }$

Explanation:

It often helps to write the heat as if it were a reactant or a product in the thermochemical equation.

Then you can consider it to be 11018 "moles" of "kJ"

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r: 32.00

2C₈H₁₈ + 25O₂ ⟶ 16CO₂ + 8H₂O + 11 018 kJ

n/mol: 7280

1. Moles of O₂

The molar ratio is 25 mol O₂:11 018 kJ

$\text{Moles of O}_{2} = \text{7280 kJ} \times \dfrac{\text{25 mol O}_{2}}{\text{11 018 kJ}} = \text{16.52 mol O}_{2}$

2. Mass of O₂

$\text{Mass of C$_{8}$H}_{18} = \text{16.52 mol O}_{2} \times \dfrac{\text{32.00 g O}_{2}}{\text{1 mol O}_{2}} = \textbf{528.6 g O}_{2}\\\text{The reaction requires $\large \boxed{\textbf{528.67 g O}_{2}}$}$

3 0

2 years ago

How does a system at equilibrium respond to the addition of more reactant

grin007 [14]

Answer:

It favors the forward reaction.

Explanation:

According to Le Chatelier's Principle, when a system at equilibrium suffers a perturbation, the system will react in order to counteract the effect of such perturbation.

If more reactant is added, the system will try to decrease its concentration. It will do so by favoring the forward reaction, decreasing the concentration of the reactant and increasing the concentration of the products, in order to re-establish the equilibrium.

7 0

3 years ago