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Oksana_A [137]
3 years ago
5

Someone help please I don’t know the answer to the question I meeed help

Chemistry
1 answer:
mihalych1998 [28]3 years ago
5 0

Answer: 143.3  

137+115+104+263+98 divided by 5.Which gives us 143.3

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zvonat [6]

should be ocean ridges im not sure hope this helps tho

6 0
3 years ago
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Identify the process in which the entropy increases. Identify the process in which the entropy increases. the phase transition f
diamong [38]

Answer:

The phase transition from a solid to a gas.

Explanation:

Entropy is related to the moles of gases available. The more gaseous moles, the higher the entropy.

<em>Identify the process in which the entropy increases.</em>

  • <em>the phase transition from a solid to a gas</em>. YES. There are more gaseous moles available so entropy increases.
  • <em>a decrease in the number of moles of a gas during a chemical reaction</em>. NO. This causes a decrease in entropy.
  • <em>the phase transition from a liquid to a solid</em>. NO. There is almost no change in the entropy in this process.
  • <em>the phase transition from a gas to a liquid</em>. NO. There is a decrease in entropy in this process.
  • <em>the phase transition from a gas to a solid</em>. NO. There is a decrease in entropy in this process.
7 0
4 years ago
The titration of 25.00 ml a 0.125 m hclo4 solution requires 27.07 ml of koh to reach the endpoint. what is the concentration of
agasfer [191]

Answer : The concentration of the KOH is, 0.115 M

Explanation :

Using dilution law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity of an acid = 1

n_2 = acidity of a base = 1

M_1 = concentration of HClO_4 = 0.125 M

M_2 = concentration of KOH = ?

V_1 = volume of HClO_4 = 25 ml

V_2 = volume of NaOH = 27.07 ml

Now put all the given values in the above law, we get the concentration of the KOH.

1\times 0.125M\times 25ml=1\times M_2\times 27.07ml

M_2=0.115M

Therefore, the concentration of the KOH is, 0.115 M

5 0
4 years ago
I will give you a brainliest.
Zina [86]

answer= 0.912 L or 912 mL

M(KClO3) =  122.55 g/mol

3.00 g KClO3 * 1  mol/122.55 g = 3.00/122.55 mol =0.02449 mol                

                          2KCIO3(s)=2KCI(s) + 3O2(g)

from reaction      2 mol                         3 mol

given                   0.02449 mol              x

x = 0.02449*3/2 =0.03673 mol O2

T = 24 + 273.15 = 297.15 K

PV = nRT

V= nRT/P = (0.03673 mol*0.082057 L*atm/K*mol*297.15 K)/0.982 atm =

= 0.912 L or 912 mL

8 0
3 years ago
Please help y’all I don’t understand
ycow [4]

Answer:

Both atoms achieve a more stable configuration

Explanation:

3 0
3 years ago
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