Factor the following:
6 x^2 - 19 x + 10
Factor the quadratic 6 x^2 - 19 x + 10. The coefficient of x^2 is 6 and the constant term is 10.
The product of 6 and 10 is 60. The factors of 60 which sum to -19 are -4 and -15.
So 6 x^2 - 19 x + 10 = 6 x^2 - 15 x - 4 x + 10 = 2 x (3 x - 2) - 5 (3 x - 2):
2 x (3 x - 2) - 5 (3 x - 2)
Factor 3 x - 2 from 2 x (3 x - 2) - 5 (3 x - 2):
Answer: (3 x - 2) (2 x - 5)
0.56 4 and below round it down, 5 and above round it up.
9514 1404 393
Answer:
z = (xy)/(x+y)
Step-by-step explanation:
Taking logarithms base 10, we have ...
x·log(2) = y·log(5) = z·log(10)
z = x·log(2) = y·log(5) . . . . . . . . log(10) = 1
__
Then z/x = log(2), and z/y = log(5), so ...
z/x +z/y = log(2) +log(5) = log(2·5) = 1
z = 1/(1/x +1/y) = 1/((x+y)/(xy))
z = (xy)/(x+y)
When n = 1 first term = -6
n = 2 second term = 0
n = 3 third term = 6
n = 4 4th term = 12
so we have an Arithmetic sequence first term = -6 and common difference = 6
Sum 14 terms = (14/2)[2*-6 + (14-1)*6]
= 462 answer
Answer:
No
Step-by-step explanation:
If OR = 20,
PR = 5
<u><em>OP would be</em></u>:
=> 20+5
=> 25
