Answer:
v = ((M(√2gH)/3m)
Explanation:
Initial Moment of Inertia= Moment of Inertia of Rod
I = (ML²)/3
Linear Velocity of moveable end of the rod, just before collision is given by = v = (√2gH)/L
Initial Angular Momentum, about the point of the suspension:
Li= Iw = {(ML²)/3} . {(√2gH)/L} = {ML(√2gH)}/3
Final Angular Momentum = Li = mvl, where 'v' is the speed of the mass 'm' after the collision
Since the collision is elastic, all momentum will be conserved, which means
Initial Angular Momemtum = Final Angular Momentum
{ML(√2gH)}/3 = mvL
solving for v = {(M)/3m} . {(√2gH)/L}
Answer:
the correct answer is TRUE
Hope it helps you
have a nice day
Explanation:
Equilibrium position in y direction:
W = Fb (Weight of the block is equal to buoyant force)
m*g = V*p*g
V under water = A*h
hence,
m = A*h*p
Using Newton 2nd Law
Hence, T time period
T = 2*pi*sqrt ( h / g )
C. endothermic
An endothermic process takes heat from the surroundings while an exothermic process gives out heat to the surroundings.
Answer:
An estimate for the time it will take for a spacecraft to travel from Earth to Mars is approximately 138.8 days
Explanation:
The distance between Earth and the Moon = 684,400 km
The distance between Earth and Mars = 220.58 × 10⁶ km
The distance between Earth and Pluto = 5.2241 × 10⁹ km
The ratio of the distance between Earth and Pluto and the distance between Earth and Mars = (5.2241 × 10⁹ km)/(220.58 × 10⁶ km) ≈ 23.683
It took 2006 to 2015 (9 years) to travel from Earth to Pluto, therefore, it can take approximately (9 years)/(23.683) ≈ 0.38 of a year which is ((9 years)/(23.683)) × 365.2422 ≈ 138.8 days for a spacecraft to travel from Earth to Mars
