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Pavlova-9 [17]
3 years ago
11

Camouflage is to blend in with what​

Physics
1 answer:
Elanso [62]3 years ago
8 0
To blend in with your surroundings
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In most materials, as heat energy is absorbed, density
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Answer:

In most materials, as heat energy is absorbed, the density decreases. IF a certain object is heated, it might appear bigger than usual because it expands as the molecules inside moves faster than usual. However the mass of it stays the same while the density decreases.

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3 years ago
What is the electric potential at a point between the 2.5-ω and 5.5-ω resistors, if the electric potential at the positive termi
algol13
If the +12V is on one side of the 2.5 ohm R then.............

V = (2.5/8) x 12     otherwise......

V = (5.5/8) x 12


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3 years ago
An object's weight is what to it's mass
oee [108]

object's weight is the independent of mass and gravity .

Weight = mass × gravity

5 0
3 years ago
A ball of mass 0.50 kg is fired with velocity 160 m/s into the barrel of a spring gun of mass 1.8 kg initially at rest on a fric
shepuryov [24]

Answer:

All fraction of kinectic energy is lost to barrel of a spring gun of mass 1.8 kg

Explanation:

A ball of mass 0.50 kg is fired with velocity 160 m/s ...

The kinetic energy is given by 1/2mv²

Kinectic energy of the ball = 1/2 *0.5*160²

Kinectic energy = 1/4 *25600

Kinectic energy = 6400 joules.

If no energy is lost to fiction, and the ball sticks to a barrel of a spring gun of mass 1.8 kg with initial velocity zero, all kinetic energy is lost to the barrel of a spring gun of mass 1.8 kg.

5 0
3 years ago
A box rests on the (horizontal) back of a truck. The coefficient of static friction between the box and the surface on which it
vredina [299]

Answer:

The distance is 11 m.

Explanation:

Given that,

Friction coefficient = 0.24

Time = 3.0 s

Initial velocity = 0

We need to calculate the acceleration

Using newton's second law

F = ma...(I)

Using formula of friction force

F= \mu m g....(II)

Put the value of F in the equation (II) from equation (I)

ma=\mu mg....(III)

a = \mu g

Put the value in the equation (III)

a=0.24\times9.8

a=2.352\ m/s^2

We need to calculate the distance,

Using equation of motion

s = ut+\dfrac{1}{2}at^2

s=0+\dfrac{1}{2}2.352\times(3.0)^2

s=10.584\ m\ approx\ 11\ m

Hence, The distance is 11 m.

3 0
3 years ago
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