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Pavlova-9 [17]
3 years ago
11

Camouflage is to blend in with what​

Physics
1 answer:
Elanso [62]3 years ago
8 0
To blend in with your surroundings
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How long have advances in astronomy been occurring? Only for the past few years
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I'd have to say that the list of choices doesn't go far enough.

Advances in Astronomy have been occurring for at least the past two millennia (2000 years).  Maybe longer.

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4 years ago
Which of the following wire gage sizes is the thickest? <br> A. 8<br> B. 10<br> C. 14<br> D. 0
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A because it's the smaller the thicker you just can't have 0 gage
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An spring has a period of 4 seconds. What is its frequency?
trasher [3.6K]

Answer:

2Hz

Explanation:

Hope this helps

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3 years ago
Which one of the following acts is an example of body language?
just olya [345]
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4 years ago
Read 2 more answers
Two current-carrying wires are parallel to each other. The current in one is increased by a factor of 2 , the current in the oth
ladessa [460]

Answer:

The new force F_N will be \frac{6}{13} times the old force F. The change then will be \Delta F=-\frac{7}{13}F

Explanation:

The force between two current-carrying parallel wires is calculated with the formula:

F=\frac{\mu_0I_1I_2\Delta L}{2\pi r}

where r is the distance between them, \Delta L a portion of length of the wires we consider, I_1 and I_2 their current intensity and \mu_0=4\pi\times10^{-7}N/A^2 the vacuum permeability.

If the current in one wire is increased by a factor of 2, the current in the other is increased by a factor of 3 , and the distance between the wires is decreased by a factor of 13, then we would have a new situation N where (considering the previous variables as an initial situation):

I_{N1}=2I_1\\I_{N2}=3I_2\\r_N=13r\\

And the force then will be:

F_N=\frac{\mu_0I_{N1}I_{N2}\Delta L}{2\pi r_N}=\frac{\mu_02I_13I_2\Delta L}{2\pi 13r}=\frac{6(\mu_0I_1I_2\Delta L)}{13(2\pi r)}=\frac{6}{13}F

So the change will be:

\Delta F=F_N-F=\frac{6}{13} F-F=(\frac{6}{13} -1)F=-\frac{7}{13}F

5 0
3 years ago
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