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Katena32 [7]
3 years ago
5

A gas is compressed at constant temperature from a volume of 5.68 L to a volume of 2.35 L by an external pressure of 732 torr. C

alculate the work done in J
Physics
1 answer:
Vlada [557]3 years ago
5 0

Answer: The work done in J is 324

Explanation:

To calculate the amount of work done for an isothermal process is given by the equation:

W=-P\Delta V=-P(V_2-V_1)

W = amount of work done = ?

P = pressure = 732 torr = 0.96 atm    (760torr =1atm)

V_1 = initial volume = 5.68 L

V_2 = final volume = 2.35  L

Putting values in above equation, we get:

W=-0.96atm\times (2.35-5.68)L=3.20L.atm

To convert this into joules, we use the conversion factor:

1L.atm=101.33J

So, 3.20L.atm=3.20\times 101.3=324J

The positive sign indicates the work is done on the system

Hence, the work done for the given process is 324 J

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Two small identical conducting spheres are placed with their centers 0.41 m apart. One is given a charge of 12 ✕ 10−9 C, the oth
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(a) -1.48\cdot 10^{-5}N

The electrostatic force exerted between the two sphere is given by:

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the charges on the two spheres

r is the separation between the centres of the two spheres

In this problem,

q_1 = 12\cdot 10^{-9} C\\q_2 = -23\cdot 10^{-9} C\\r = 0.41 m

Substituting these values into the equation, we find the force

F=(9\cdot 10^9 Nm^2 C^{-2} )\frac{(12\cdot 10^{-9}C)(-23\cdot 10^{-9} C)}{(0.41 m)^2}=-1.48\cdot 10^{-5}N

And the negative sign means the force is attractive, since the two spheres have charges of opposite sign.

(b) +1.62\cdot 10^{-6}N

The total net charge over the two sphere is:

Q=q_1 +q_2 = 12\cdot 10^{-9}C+(-23\cdot 10^{-9}C)=-11\cdot 10^{-9} C

When the two spheres are connected, the charge distribute equally over the two spheres (since they are identical, they have same capacitance), so each sphere will have a charge of

q=\frac{Q}{2}=\frac{-11\cdot 10^{-9}C}{2}=-5.5\cdot 10^{-9}C

So the electrostatic force between the two spheres will now be

F=k\frac{q^2}{r^2}

And substituting numbers, we find

F=(9\cdot 10^9 Nm^2 C^{-2} )\frac{(-5.5\cdot 10^{-9} C)^2}{(0.41 m)^2}=+1.62\cdot 10^{-6}N

and the positive sign means the force is repulsive, since the two spheres have same sign charges.

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