Answer:
Step-by-step explanation:
10+6 = 16
A is correct answer
The circle equation is in the format (x – h)2 + (y – k)2= r2, with the center being at the point (h, k) and the radius being "r".
x²+y²-8x-6y+2 =0 -----(a)
(x-4)² = x² - 8x + 16
(y-3)² = y² - 6y + 9
Equation (a) can be rewritten as:
(x-4)² + (y-3)² + 2 - 16 - 9 = 0
(x-4)² + (y-3)² = 23
The coordinates for the center of the circle is: ( 4,3)
The radius is √23=4.8
Answer:
(x1,y1) = (2x - x2, 2y - y2)
Step-by-step explanation:
Given:
Midpoint = (x , y)
End point = (x2, y2)
Find:
(x1, y1)
Computation:
Mid-point formula
x = (x1 + x2) / 2 , y = (y1 + y2) / 2
So,
2x = x1 + x2 , 2y = y1 + y2
x1 = 2x - x2 , y1 = 2y - y2
So,
(x1,y1) = (2x - x2, 2y - y2)
