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horrorfan [7]
3 years ago
6

In the figure below, mZ1 =(x+44) and mZ2=3xº. Find the angle measures.

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
6 0

Answer:

where is the diagram? please provide the diagram.

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X^2-18x+67=0 Solve the quadratic equation by completing the square.
Assoli18 [71]

Answer:

x = 9 ± √14

Step-by-step explanation:

x² − 18x + 67 = 0

Move the constant to the other side:

x² − 18x = -67

Take half of -18, square it, and add to both sides.

(-18/2)² = (-9)² = 81

x² − 18x + 81 = -67 + 81

x² − 18x + 81 = 14

Factor the perfect square:

(x − 9)² = 14

Solve for x:

x − 9 = ±√14

x = 9 ± √14

5 0
3 years ago
This is line segments
lianna [129]

Step-by-step explanation:

here \: given \: that \: total \: lenth = bd = 67 \\ then \: bd = bc + cd \\ so \: we \: can \: write \: that \\ 67 = 3x - 2 + 4x + 13 \\67 =  3x + 4x - 2 + 13 \\ 67 = 7x + 11 \\ 7x = 67 - 11 \\ 7x = 56 \\ x =  \frac{56}{7}  \\ x = 8 \\ thankyou

8 0
3 years ago
Read 2 more answers
Which best estimate of the sum of 5 1/5 and 8 5/6
Reika [66]

Answer:

14 1/30

Step-by-step explanation:

convert the fractions so that the LCF is the denominator

1/5---->6/30

5/6----->25/30

5 6/30+8 25/30

13 31/30

14 1/30

7 0
3 years ago
A catering service offers 5 appetizers,4 main courses, and 8 desserts. A customer is to select 4 appetizers,2 main courses,and 3
Alisiya [41]

Answer:

468 ways

Step-by-step explanation:

Given: A catering service offers 5 appetizers, 4 main courses, and 8 desserts

To find: number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts.

Solution:

A permutation is an arrangement of elements such that order of elements matters and repetition is not allowed.

Number of appetizers = 5

Number of main courses = 4

Number of desserts = 8

Number of ways of choosing k terms from n terms = nPk=\frac{n!}{(n-k)!}

Number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts =  5P4+4P2+8P3

=\frac{5!}{(5-4)!}+\frac{4!}{(4-2)!}+\frac{81}{(8-3)!}\\=5!+\frac{4!}{2!}+\frac{8!}{5!}\\=5!+(4\times 3)+(8\times 7\times 6)\\=120+12+336\\=468

So, this can be done in 468 ways.

7 0
3 years ago
1.3 lesson help please
Airida [17]

Answer:

1. 125

2. 25

3. 40

4. 39

First question:

(15-10)^2 + (15-5)^2

parentheses first to get 5^2 + (15-5)^2

exponents next to get 25 + (15-5)^2

parentheses again 25 + 10^2

exponents again 25 + 100 = 125

Second question:

simplify the exponents (3 *3) + (4 * 4) + (2 * 2) to get 9 + 16 + 4 = 29

Third question:

simplify in the parentheses 6 1/7 - 1/7 = 6

divide 60 by 6 to get 10

multiply 10 by 4 to get 40!

Fourth question:

simplify the fractions to get 1/3 + 8/3 = 3

multiply the 3 by 13 to get 39

7 0
2 years ago
Read 2 more answers
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