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horrorfan [7]
3 years ago
6

In the figure below, mZ1 =(x+44) and mZ2=3xº. Find the angle measures.

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
6 0

Answer:

where is the diagram? please provide the diagram.

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The letters for the word SCHOOL are placed in a hat. What is the probability of drawing the letter O out of the hat?
cluponka [151]
This would be 2/6 chances or percentage form about 33%
3 0
3 years ago
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To convert 0.73 hours into minutes which ratio would you multiply by. a 1 minute/ 60 hours
Serjik [45]
60 min / 1 hour. ...
4 0
4 years ago
The first 2 terms of an ap is -2 and 3 how many terms are needed for the sum to be equal to 306 ​
Zepler [3.9K]

Answer:

306

Step-by-step explanation:

-2 + 3 = 1

so really it would take 306 times to get to this

6 0
4 years ago
A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) A
julsineya [31]

Answer:

a) -13.9 ft/s

b) 13.9 ft/s

Step-by-step explanation:

a) The rate of his distance from the second base when he is halfway to first base can be found by differentiating the following Pythagorean theorem equation respect t:

D^{2} = (90 - x)^{2} + 90^{2}   (1)

\frac{d(D^{2})}{dt} = \frac{d(90 - x)^{2} + 90^{2})}{dt}

2D\frac{d(D)}{dt} = \frac{d((90 - x)^{2})}{dt}  

D\frac{d(D)}{dt} = -(90 - x) \frac{dx}{dt}   (2)

Since:

D = \sqrt{(90 -x)^{2} + 90^{2}}

When x = 45 (the batter is halfway to first base), D is:

D = \sqrt{(90 - 45)^{2} + 90^{2}} = 100. 62

Now, by introducing D = 100.62, x = 45 and dx/dt = 31 into equation (2) we have:

100.62 \frac{d(D)}{dt} = -(90 - 45)*31          

\frac{d(D)}{dt} = -\frac{(90 - 45)*31}{100.62} = -13.9 ft/s

Hence, the rate of his distance from second base decreasing when he is halfway to first base is -13.9 ft/s.

b) The rate of his distance from third base increasing at the same moment is given by differentiating the folowing Pythagorean theorem equation respect t:

D^{2} = 90^{2} + x^{2}  

\frac{d(D^{2})}{dt} = \frac{d(90^{2} + x^{2})}{dt}

D\frac{dD}{dt} = x\frac{dx}{dt}   (3)

We have that D is:

D = \sqrt{x^{2} + 90^{2}} = \sqrt{(45)^{2} + 90^{2}} = 100.63

By entering x = 45, dx/dt = 31 and D = 100.63 into equation (3) we have:

\frac{dD}{dt} = \frac{45*31}{100.63} = 13.9 ft/s

Therefore, the rate of the batter when he is from third base increasing at the same moment is 13.9 ft/s.

I hope it helps you!

4 0
3 years ago
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Are the corresponding sides of similar hexagons are always congruent
Lerok [7]
Two polygons are similar if their corresponding angles are congruent and their sides are in proportion.

The sides could be in a ration of 1:1 in which case the two hexagons have corresponding sides that are congruent, but they do not have to be. It could be the case that the sides of one are twice the length of the other so the ratio is 2:1. In this case the hexagons have the same shape but not the same size.

So the answer is this, the corresponding sides of similar hexagons may be congruent but do not have to be.
7 0
3 years ago
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