3 years ago

In the figure below, mZ1 =(x+44) and mZ2=3xº. Find the angle measures.

Mathematics

1 answer:

Evgesh-ka [11]3 years ago

6 0

Answer:

where is the diagram? please provide the diagram.

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How can I solve 900-382?

BlackZzzverrR [31]

899

900

- 382

<h3> 517</h3><h3>Hope this helps</h3>

6 0

3 years ago

Please help I don’t understand

Archy [21]

Answer:

Step-by-step explanation:

when you draw a line through both it show that the are parallel and will never touch.

6 0

2 years ago

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Use the functions f(x) = 4x − 5 and g(x) = 3x + 9 to complete the function operations listed below.

JulijaS [17]

A:

(f+g)(x)=f(x)+g(x)

(f+g)(x)=4x-5+3x+9

(f+g)(x)=7x+4

B:

(f•g)(x)=f(x)•g(x)

(f•g)(x)=(4x-5)(3x+9)

(f•g)(x)=12x^2-15x+36x-45

(f•g)(x)=12x^2+21x-45

C:

(f○g)(x)=f(g(x))

(f○g)(x)=4(3x+9)-5

(f○g)(x)=12x+36-5

(f○g)(x)=12x+31

6 0

3 years ago

A car rental company charges a one-time application fee of 40 dollars, 55 dollars per day, and 13 cents per mile for its cars. A

liberstina [14]

Answer:

A) C(d,m) = 40 + 55d + 0.13m

B) $448

Step-by-step explanation:

Let 'd' be the number of days and 'm' the number of miles driven.

A) The cost function that describes a fixed amount of $40, added to a variable amount of $55 per day (55d) and a variable amount of 13 cents per mile (0.13m) is:

$C(d,m) = 40 +55d +0.13m$

B) If d = 5 and m =600, the total cost is:

$C(5,600) = 40 +55*6 +0.13*600\\C(5,600)=\$448$

The cost is $448.

3 0

3 years ago

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Simplify (a+b)^3 + (a-b)^3 + 6a(a^2-b^2)

11111nata11111 [884]

Answer:

8a^3.

Step-by-step explanation:

(a+b)^3=a^3+b^3+3a^2b+3ab^2

(a-b)^3=a^3-b^3-3a^2b+3ab^2

(a+b)^3+(a-b)^3=2a^3+6ab^2

According to the question

(a+b)^3+(a-b)^3+6a(a^2-b^2)

Put in the value

=2a^3+6ab^2 +6a^3–6ab^2

=8a^3

7 0

3 years ago