Since there is no weight, I would assume that this is a 100g of pure compound.
Okay so I would be changing the percentage to gram to solve for the mole.
So
40.0g C (1 mol C/12.01 g C) = 3.33 mol C
6.73g H (1 mol H/1.01 g H ) = 6.66 mol H
53.3g O (1 mol O/16.00 g O) = 3.33 mol O
With that, two of our moles is 3.33, so we consider that are our 1, as it is also the lowest. Therefore the empirical formula is CH2O
The answer should be B - Nitrogen Dioxide.
Answer:
solvent (such as water, oil or isopropyl alcohol) is allowed to absorb up the paper strip. ... Different molecules run up the paper at different rates. As a result, components of the solution separate and, in this case, become visible as strips of color on the chromatography paper.
Explanation:
Hope this helps leave a heart c:
Answer:
D). Much lower than
Explanation:
When a ketone and its enol are in equilibrium, under most conditions the concentration of the enol is <u>Much lower than</u> the concentration of the ketone
because :
Carbon- oxygen bond is more stable(stronger) than Carbon-Carbon Bond
Keto - enol tautomerism is :
Ketone has C=O and enol has C=C
C=O bond energy is 745 kJ/mol
C=C bond energy is 614 kJ/mol
Answer:
TY and I like the country studies.
Explanation:
ok bye por a mathmu n bye for now and hope you have patience.
