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3 years ago

Using the periodic table as a reference, which elements could bond to form a compound most like NaCl?

Chemistry

1 answer:

pychu [463]3 years ago

4 0

step by step

Na(sodium)=2.8.1

Cl (Chlorine)=2.8.7. sodium will give the chlorine the 1 valence electron to become stable ions.

answer

pottasium. (2.8.8.1) and Flourine(2.7)

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For the reaction NH4NO3 (s) → N2O (g) + 2H2O (l), you decompose 1 mole NH4NO3 and only get 0.75 moles of N2O. The percent yield

attashe74 [19]

Answer:

The answer to your question is False.

Explanation:

Data

1 mole of NH₄NO₃

0.75 moles of N₂O

Percent yield = 25%

Chemical reaction

NH₄NO₃ ⇒ N₂O + 2H₂O

Process

1.- Determine the theoretical yield

1 mol NH₄NO₃ ------------- 1 mol of N₂O

2.- Calculate the percent yield

Percent yield = Actual yield / Theoretical yield x 100

-Substitution

Percent yield = 0.75 / 1 x 100

-Simplification

Percent yield = 0.75 x 100

-Result

Percent yield = 75%

Conclusion

False, the actual percent yield is 75%

5 0

3 years ago

if you could place a piece of solid silver into a container of liquid silver, would it float or sink? Explain your answer

olga55 [171]

Liquid silver is less dense than solid silver, so the solid silver would sink.

5 0

3 years ago

Read 2 more answers

Calculate the specific heat capacity for a 15.3-g sample of gold that absorbs 87.2 J when its temperature increases from 35.0 °C

diamong [38]

Answer:

The specific heat of gold is 0.129 J/g°C

Explanation:

Step 1: Data given

Mass of gold = 15.3 grams

Heat absorbed = 87.2 J

Initial temperature = 35.0 °C

Final temperature = 79.2 °C

Step 2:

Q = m*c*ΔT

⇒ Q =the heat absorbed = 87.2 J

⇒ m = the mass of gold = 15.3 grams

⇒ c = the specific heat of gold = TO BE DETERMINED

⇒ ΔT = The change in temperature = T2 - T1 = 79.2 - 35.0 = 44.2 °C

87.2 J = 15.3g * c * 44.2°C

c = 87.2 / (15.3 * 44.2)

c = 0.129 J/g°C

The specific heat of gold is 0.129 J/g°C

4 0

3 years ago

Most people like to go outside on a sunny day, but too much sun exposure can cause sunburns as well as long term health problems

ss7ja [257]

Earths atmosphere protects you from the sun

4 0

3 years ago

Read 2 more answers

How many moles of water were lost if the amount of water lost was 0.456 grams? Do not include units and assume three significant

nika2105 [10]

<h3>Answer:</h3>

0.0253 mol H₂O

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table

Stoichiometry

Using Dimensional Analysis

<h3>Explanation:</h3>

Step 1: Define

[Given] 0.456 g H₂O (water)

Step 2: Identify Conversions

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Step 3: Convert

[DA] Set up: $\displaystyle 0.456 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 0.025305 \ mol \ H_2O$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.025305 mol H₂O ≈ 0.0253 mol H₂O

3 0

2 years ago