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Marina86 [1]
3 years ago
8

Four forces are exerted on each of the two objects shown below:

Chemistry
1 answer:
zzz [600]3 years ago
4 0

Answer:

A: Object A will move in the up direction. But not object B

Explanation:

It will move in the up direction because object A has an unbalanced force. For the up direction there, it is 6 newtons and for the bottom direction, it is 2 newtons. For the right and left direction, both of them are 3 newtons. So object A will move in the up direction because it has the most newtons(which is 6).

For Object B, it is unbalanced too. But object B will move to the right because it is 2 newtons there and there is one newton on the left. Furthermore, the up and down directions are 3 newtons. So they are balanced and will cancel out. Therefore, object A will move in the right direction because it has the most newtons(which is 3).

So the final answer is object A. Hope it helped!

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As a liquid is added to a beaker, the pressure exerted by the liquid on the bottom of the beaker does what
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Explain how astronomers use spectrographs to identify the composition of a star.
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3 years ago
Phenolphthalein has a pKa of 9.7 and is colorless in its acid form and pink in its basic form. calculate [In-}/{HIn} for the fol
zvonat [6]

Answer:

1.58x10⁻⁵

2.51x10⁻⁸

0.0126

63.10

Explanation:

Phenolphthalein acts like a weak acid, so in aqueous solution, it has an acid form HIn, and the conjugate base In-, and the pH of it can be calculated by the Handerson-Halsebach equation:

pH = pKa + log[In-]/[HIn]

pKa = -logKa, and Ka is the equilibrium constant of the dissociation of the acid. [X] is the concentrantion of X. Thus,

i) pH = 4.9

4.9 = 9.7 + log[In-]/[HIn]

log[In-]/[HIn] = - 4.8

[In-]/[HIn] = 10^{-4.8}

[In-]/[HIn] = 1.58x10⁻⁵

ii) pH = 2.1

2.1 = 9.7 + log[In-]/[HIn]

log[In-]/[HIn] = -7.6

[In-]/[HIn] = 10^{-7.6}

[In-]/[HIn] = 2.51x10⁻⁸

iii) pH = 7.8

7.8 = 9.7 + log[In-]/[HIn]

log[In-]/[HIn] = -1.9

[In-]/[HIn] = 10^{-1.9}

[In-]/[HIn] = 0.0126

iv) pH = 11.5

11.5 = 9.7 + log[In-]/[HIn]

log[In-]/[HIn] = 1.8

[In-]/[HIn] = 10^{1.8}

[In-]/[HIn] = 63.10

6 0
3 years ago
The concentration of pb2+ in a solution saturated with pbbr2(s) is 2.14 ✕ 10-2 m. calculate ksp for pbbr2.
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Concentration = 2.14 âś• 10-2 m 
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