Answer:
12.6.
Explanation:
- We should calculate the no. of millimoles of KOH and HCl:
no. of millimoles of KOH = (MV)KOH = (0.183 M)(45.0 mL) = 8.235 mmol.
no. of millimoles of HCl = (MV)HCl = (0.145 M)(35.0 mL) = 5.075 mmol.
- It is clear that the no. of millimoles of KOH is higher than that of HCl:
So,
[OH⁻] = [(no. of millimoles of KOH) - (no. of millimoles of HCl)] / (V total) = (8.235 mmol - 5.075 mmol) / (80.0 mL) = 0.395 M.
∵ pOH = -log[OH⁻]
∴ pOH = -log(0.395 M) = 1.4.
∵ pH + pOH = 14.
∴ pH = 14 - pOH = 14 - 1.4 = 12.6.
The frequency of the radiation is equal to
Hertz.
<u>Given the following data:</u>
- Photon energy =
Joules
To find the frequency of this radiation, we would use the Planck-Einstein equation.
Mathematically, the Planck-Einstein relation is given by the formula:

<u>Where:</u>
Substituting the given parameters into the formula, we have;

Frequency, F =
Hertz
Read more: brainly.com/question/16901506
Answer:
frequency of light (f) = 1 x 10¹⁵s⁻¹
Explanation:
Given Data:
Wavelength of light λ = 3.0 x10⁻⁷m
Frequency of light: to be calculated
Formula Used to find frequency:
f = V/λ ........................... (1)
where
f is the frequency
V is the velocity
λ is wavelength
Velocity of light = 3 x 10⁸ ms⁻¹
put the values in equation (1)
f = 3 x 10⁸ ms⁻¹ / 3.0 x10⁻⁷m
f = 1 x 10¹⁵s⁻¹
So the frequency of light = 1 x 10¹⁵s⁻¹
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