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3 years ago

How many moles of copper would be needed to make one mole of cu2o?

Chemistry

1 answer:

julia-pushkina [17]3 years ago

5 0

Answer:

Explanation:

You can view more details on each measurement unit: molecular weight of Copper(I) Oxide or grams The molecular formula for Copper(I) Oxide is Cu2O. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Copper(I) Oxide, or 143.0914 grams.

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An acid solution is 0.100 M in HCl and 0.210 M in H2SO4. What volume of a 0.150 M solution of KOH must be added to 500.0 mL of t

Dmitry_Shevchenko [17]

Answer:

When we add 0.33L of KOH only the HCl solution will be neutralized. When we add 1.4 L of KOH, all of the acid (the HCl and H2SO4 solution) will be neutralized.

Explanation:

Step 1: Data given

The solution has 0.100 M HCl and 0.210 M H2SO4

Molarity KOH = 0.150 M

Volume of acid solution = 500 mL = 0.5 L

Step 2: Calculate moles of HCl

Moles HCl = Molarity HCl * volume

Moles HCl = 0.100 M * 0.5 L

Moles HCl = 0.05 moles

Step 3: Calculate moles of H2SO4

Moles H2SO4 = 0.210 M * 0.5 L

Moles H2SO4 = 0.105 moles

Step 4: The balanced neutralization reaction of KOH with HCl can be written as:

KOH + HCl → KCl + H2O

The mole ratio is 1:1

This means to neutralize 0.05 moles HCl, we need 0.05 moles KOH

Step 5: The balanced neutralization reaction of KOH with H2SO4 can be written as:

2KOH + H2SO4 → K2SO4 + 2H2O

The mole ratio KOH: H2SO4 is 2:1

This means to neutralize 0.105 moles H2SO4 we need 0.210 moles KOH

Step 6: Calculate volume of KOH needed to neutralize the solution

To neutralize the HCl solution: 0.05 moles / 0.150 M = 0.33 L KOH needed

To neutralize the H2SO4 solution: 0.210 moles / 0.150 M = 1.4 L KOH needed

When we add 0.33L of KOH the HCl solution will be neutralized. When we add 1.4 L of KOH the HCl and H2SO4 solution will be neutralized.

4 0

3 years ago

Which of the following is a physical property?

taurus [48]

Boiling Point is a physical property because It is the the only one that doesn’t require a chemical reaction

8 0

3 years ago

As the elements of Group 17 are considered in order of increasing atomic number, there is an increase in

11111nata11111 [884]

Alright so the way I see it by definition of increasing atomic number of the halogen family, that means you're going down the periodic table. Therefore, there's an increase in the number of outer shells. The atomic radius would increase because that's basically the distance between the nucleus of the element to the outermost electron. More electron shells=Greater distance=Larger atomic radius

3 0

3 years ago

Urgent

morpeh [17]

We can achieve equilibrium state, when the concentration of product and reactants are equal to each other.

<h3>Describe this system when it reaches phase equilibrium?</h3>

In this type of system, when the same amount of liquid water is converted into gaseous form of water and the gaseous form of water into liquid form of water. This phase is known as equilibrium phase or state because same amount of reactants and products are produced .

So we can conclude that we can achieve equilibrium state, when the concentration of product and reactants are equal to each other.

Learn more about equilibrium here: brainly.com/question/517289

#SPJ1

6 0

2 years ago

Mass of an empty 50 litres cylinder is 4.8kg. the cylinder is filled with 60atm nitrogen gas. molecular mass of nitrogen is 28.

padilas [110]

Answer:

8.235 kg

Explanation:

Mass of the cylinder = 4.8 kg

The capacity (volume) of the cylinder = 50 liters

As 1 m^3 = 1000 liters

So, the volume of the cylinder, v= 0.05 m^3

The volume of filled nitrogen, v= 0.05 m^3

Pressure of filled nitrogen, p = 60 atm = 60\times 101325 Pa

Assuming that the nitrogen gas is at room temperature which is 25-degree centigrade,

So, the temperature of nitrogen gas, T=273+25= 298 K

By using the ideal gas equation, pv=nRT

Where n is the number of moles, R is the universal gas constant, R = 8.314 J/mol·K

Putting all the values in the ideal gas equation, we have

(60 x 101325)0.05 = n (8.314) x (298)

n= (60 x 101325 x 0.05)/(8.314 x 298)

n=122.69 moles

As the molar mass of nitrogen is 28, so the total mass of the nitrogen in the cylinder, m= 122.69 x 28 = 3435.32 grams = 3.435 kg.

Hence, the new mass of the cylinder = 4.8+3.435=8.235 kg

7 0

3 years ago