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Paraphin [41]
3 years ago
7

15.630 g milk chocolate bar ks found to contain 9.815g of sugar. how many milligrams of sugar does the bar contain?

Chemistry
2 answers:
goldenfox [79]3 years ago
8 0

<u>Answer:</u> The mass of sugar that the bar contains is 9815 milligrams.

<u>Explanation:</u>

We are given:

Mass of milk chocolate bar = 15.630 g

Mass of sugar in it = 9.815 g

Converting the mass from grams to milligrams, we use the conversion factor:

1 g = 1000 mg

So, 9.815g\times (\frac{1000mg}{1g})=9815mg

Hence, the mass of sugar that the bar contains is 9815 milligrams.

sleet_krkn [62]3 years ago
3 0
Well there are 1,000 milligrams in 1 gram so 9.815 grams of sugar is equivalent to 9,815 milligrams of sugar. So a bar of milk chocolate contains 9,815 milligrams of sugar.
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The percent yield of carbon dioxide will be 49.0 %.

<h3>Percent yield</h3>

First, let's look at the equation of the reaction:

2C_8H_1_8 + 25O_2 -- > 16CO_2 + 18H_2O

The mole ratio of octane to oxygen is 2:25.

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More on percent yield can be found here: brainly.com/question/17042787

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If the volume of wet gas collected over water is 85.0 mL at 20°C and 760 mm Hg , what is the volume of dry gas at STP conditions
dimulka [17.4K]

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Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

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P_1 = initial pressure of dry gas = (760 - 17.5) mmHg= 742.5 mm Hg

P_2 = final pressure of dry gas at STP =  760 mm Hg

V_1 = initial volume of dry gas = 85.0 mL

V_2 = final volume of dry gas at STP = ?

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T_2 = final temperature of dry gas at STP = 0^oC=273+0=273K

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