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Darya [45]
3 years ago
7

A student pushes a 12 kg block on a frictionless horizontal surface if the block is initially at rest what is the speed of the b

lock after the student pushes the block for five seconds with an acceleration of 2 m/s squared
Physics
1 answer:
Lina20 [59]3 years ago
4 0

Answer:

20N

Explanation:

Given parameters:

Mass of the block  = 4kg

Acceleration  = 5m/s²

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Waves from a radio station have a wavelength of 369 m. They travel by two paths to a home receiver 20.0 km from the transmitter.
Olenka [21]

Answer:

92.25m

Explanation:

In order to solve the exercise, it is necessary to apply the concept of construtive interference due to a path difference.

The formula is given by,

\delta = (m+\frac{1}{2})\frac{\lambda}{n}

where,

n is the index of refraction of the medium in which the wave is traveling

\lambda = wavelenght

\delta = is the path difference

m = integer (0,1,2,3...)

Since in this case we are dealing with an atmospheric environment, where air is predominant, we approximate n to 1.

And since we need the reflected wave,

\delta = 2x

Where x is the distance in one direction without return.

The distance must correspond to the minimum therefore m = 0, so

\delta = (m+\frac{1}{2})\frac{\lambda}{n}

\delta = ({0+\frac{1}{2})\frac{369}{1}

\delta = 184.5m

Then the minimum distance is:

x= \frac{delta}{2}

x = \frac{184.6}{2}

x = 92.25m

Therefore the minimum distance from the mountain to the receiver that produces destructive interference at the receiver is 92.25m

5 0
3 years ago
Potassium is a crucial element for the healthy operation of the human
Degger [83]

Answer:

1

  The mass of the Potassium-40 is  m_{40}} = 2.88*10^{-6} kg

2

  The Dose per year in Sieverts is   Dose_s = 26.4 *10^{-10}

Explanation:

From the question we are told that

   The isotopes of potassium in the body are Potassium-39, Potassium-40, and Potassium- 41

    Their abundance is 93.26%, 0.012% and 6.728%

   The mass of potassium contained in human body is  m = 3.0 g = \frac{3}{1000} = 0.0003 \ kg per kg of the body

    The mass of the first body is  m_1 = 80 \ kg

Now the mass of  potassium  in this body is mathematically evaluated as

       m_p =  m * m_1

substituting value

       m_p =  80  * 0.0003

      m_p  =0.024 kg

The amount of Potassium-40 present  is mathematically evaluated as

      m_{40}} =0.012% * 0.024

      m_{40}} = \frac{0.012}{100}  * 0.024

      m_{40}} = 2.88*10^{-6} kg

The dose of energy absorbed per year is mathematically represented as

          Dose  = \frac{E}{m_1}

Where E is the energy absorbed which is given as E = 1.10 MeV = 1.10 * 10^6 * 1.602*10^{-19}

    Substituting value

            Dose  = \frac{ 1.10 * 10^6 * 1.602*10^{-19}}{80}

            Dose  = 22*10^{-10} J/kg

The Dose in Sieverts is evaluated as

       Dose_s = REB * Dose

       Dose_s = 1.2 * 22*10^{-10}

       Dose_s = 26.4 *10^{-10}

             

3 0
3 years ago
PLEASE Help its 50 points!!!<br><br> What are the bonds are between protons of a silver atom?
DerKrebs [107]

Answer:

Nuclear energy

i hope i help

8 0
3 years ago
Add the following forces: 20 Newtons south, 30 newtons north, 40 newtons east, and 50 newtons west
Roman55 [17]

The north and south forces have no effect on the east and west forces.
We can handle the two groups separately.

                       (20N south)  +  (30N north)

                   =  (20N south)  +  (20N north + 10N north)

                   =                              10N north .


                       (40N east)  +  (50N west)

                   =  (40N east)  +  (40N west + 10N west)

                   =                              10N west .
5 0
3 years ago
G (where g=9.8 m/s2). If an object’s mass is m=10. kg, what is its weight?
Semenov [28]
F_{w} =m*g \\ F_{w} =10*9.8=98N
7 0
4 years ago
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