Answer:
θ ≈ 65°
Explanation:
From the question given above, the following data were obtained:
Maximum height (H) = 8 m
Range (R) = 15 m
Initial velocity (u) = v
Angle θ =?
H = u²Sine²θ / 2g
8 = v²Sine²θ / 2g
Cross multiply
8 × 2g = v²Sine²θ
16g = v²Sine²θ
Divide both side by Sine²θ
v² = 16g / Sine²θ.... (1)
R = u²Sine2θ / g
15 = v²Sine2θ / g
Cross multiply
15 × g = v²Sine2θ
15g = v²Sine2θ
Divide both side by Sine2θ
v² = 15g / Sine 2θ... (2)
Summary:
v² = 16g / Sine²θ.... (1)
v² = 15g / Sine 2θ... (2)
Equate equation 1 and 2
16g / Sine²θ = 15g / Sine 2θ
16 / Sine²θ = 15 / Sine 2θ
Recall:
Sine²θ = SineθSineθ
Sine 2θ = 2SineθCosθ
16 / Sine²θ = 15 / Sine 2θ
16 / SineθSineθ = 15 / 2SineθCosθ
16 / Sineθ = 15 / 2Cosθ
Cross multiply
15 × Sineθ = 16 × 2Cosθ
15Sineθ = 32Cosθ
Divide both side by Cosθ
15Sineθ / Cosθ = 32
Divide both side by 15
Sineθ / Cosθ = 32/15
Recall:
Sineθ / Cosθ = Tanθ
Sineθ / Cosθ = 32/15
Tanθ = 32/15
Tanθ = 2.1333
Take the inverse of Tan
θ = Tan¯¹ 2.1333
θ ≈ 65°
General formula for emf is:
emf=vBL(sin θ) ...(1)
As the angle here is 90° and sin90°=1.
So,equation (1) becomes;
emf=vBL
Putting values;
emf=(6.2)(1.5)(3.96 × 10^-3)=0.0369 volts
Answer:
+ 0.07 C
Explanation:
From the question given above, the following data were obtained:
Potential difference (V) = 12 V
Energy (E) = 0.418 J
Charge (Q) =?
The energy (E) , potential difference (V) and charge (Q) are related by the following equation:
E = ½QV
With the above formula, we can obtain the charge as follow:
Potential difference (V) = 12 V
Energy (E) = 0.418 J
Charge (Q) =?
E = ½QV
0.418 = ½ × Q × 12
0.418 = Q × 6
Divide both side by 6
Q = 0.418 / 6
Q = + 0.07 C
Answer:
The value is
Explanation:
From the question we are told that
The depth of the bottom of the trench is
The depth considered is
Generally the pressure is mathematically represented as
Here is the density of water with value
=>
=>
Converting to atmosphere
=>
=>
The picture shows an example of velocity