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statuscvo [17]
2 years ago
14

019 10.0 points

Physics
1 answer:
elena55 [62]2 years ago
8 0

Answer:

Explanation:

Distance remaining after reaction time

s = s₀ - v₀t

s = 100 - 12(0.55) = 93.4 m

v² = u² + 2as

a = (v² - u²)/2s

a = (0² - 12²) / 2(93.4) = - 0.770877944...

|a| = 0.77 m/s²

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Answer:

There are 6.87 x 1023 atoms in 1.14 mol SO3, or sulfur trioxide :

3 0
3 years ago
the maximum intensity levels of a trumpet, trombone, and a bass drum, each at a distance of 3m are 94 dB, 107dB, and 113dB respe
Gwar [14]

Answer:

β = 114 db

Explanation:

The intensity of sound in decibles is

          β = 10 log \frac{I}{I_{o}}

in most cases Io is the hearing threshold 1 10-12 W / cm²

let's calculate the intensity of each instrument

            I / I₀ = 10 (β / 10)

            I = I₀ 10 (β / 10)

trumpet

            I1 = 1 10⁻¹² 10 (94/10)

            I1 = 2.51 10⁻³ / cm²

Thrombus

           I2 = 1 10⁻¹² 10 (107/10)

           I2 = 5.01 10-2 W / cm²

low

           I3 =1 1-12    (113/10) W/cm²

            I3 = 1,995 10-1 W / cm²

when we place the three instruments together their sounds reinforce

           I_total = I₁ + I₂ + I₃

           I_ttoal = 2.51 10-3 + 5.01 10-2 + ​​1.995 10-1

           I_total = 0.00251 + 0.0501 + 0.1995

           I_total = 0.25211 W / cm²

let's bring this amount to the SI system

         β = 10 log (0.25211 / 1 10⁻¹²)

           β = 114 db

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3 years ago
Through which gas in the table will sound waves travel faster than they would
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4 0
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Air bags can be dangerous or fatal under certain circumstances. you should not sit closer than ______ inches from the steering w
pishuonlain [190]
<span>10 inches
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5 0
3 years ago
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A running mountain lion can make a leap 10.0 mlong, reaching a maximum height of 3.0 m. What is the speed of the mountain lion j
nika2105 [10]

To solve this problem we will use the kinematic equations of descriptive motion of a projectile for which both the height reached and the distance traveled are defined. From this type of movement the lion reaches a height (H) of 3m and travels a horizontal distance (R) of 10 m. Mathematically the equations that describe this movement are given as,

H = \frac{v_0^2sin^2\theta}{2g}

R = \frac{v_0^2 sin 2\theta}{g}

Dividing the two equation we have that

\frac{H}{R}=\frac{\frac{v_0^2sin^2\theta}{2g}}{\frac{v_0^2 sin 2\theta}{g}}

\frac{H}{R}= \frac{sin^2\theta}{2}*\frac{1}{sin2\theta}

\frac{H}{R}= \frac{sin^2\theta}{2}*\frac{1}{2sin\theta cos\theta}

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\frac{H}{R}= \frac{1}{4} tan\theta

Substituting values of H and R, we get

\frac{3}{10} = \frac{1}{4} tan\theta

\theta = tan^{-1} \frac{12}{10}

\theta = 50.2\°

Substituting the value of \theta in equation we get,

H = \frac{v_0^2sin^2\theta}{2g}

v_0^2 = \frac{H 2g}{sin^2\theta}

v_0^2 = \frac{3*2*9.8}{sin^2(50.2)}

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v_0 = \sqrt{99.62}

v_0 = 9.98m/s

Therefore the speed of the mountain lion just as it leaves the ground is 9.98m/s at an angle of 50.2°

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