Help please I don’t know how to do this
1 answer:
You might be interested in
The intercepts of the third degree polynomial corresponds to the zeros of the equation
y = d*(x-a)*(x-b)(x-c)
Where a, b and c are the roots of the polynomial and d an adjustment coefficient.
y = d*(x+2)*(x)*(x-3)
Lets assume d = 1, and we get
y = (x+2)*(x)*(x-3) = x^3 - x^2 - 6x
We graph the equation in the attached file.
y = d*(x-a)*(x-b)(x-c)
Where a, b and c are the roots of the polynomial and d an adjustment coefficient.
y = d*(x+2)*(x)*(x-3)
Lets assume d = 1, and we get
y = (x+2)*(x)*(x-3) = x^3 - x^2 - 6x
We graph the equation in the attached file.
Answer:
D
Step-by-step explanation:
Substitute the f(x) and g(x) into f/g
To find the domain,
Get the denominator of the fraction so 5x + 2 and equal it to 0 and find x
5x + 2 = 0
5x = -2
x =
Therefore it's D