Part I: sin (theta/2) = 1/2 So, theta/2 = sin inv(1/2) Part II: On the interval [0,2pi], theta/2 = 30 degrees i.e. pi/6 degrees or 150 degrees i.e. 5pi/6...
The intercepts of the third degree polynomial corresponds to the zeros of the equation
y = d*(x-a)*(x-b)(x-c)
Where a, b and c are the roots of the polynomial and d an adjustment coefficient.
y = d*(x+2)*(x)*(x-3)
Lets assume d = 1, and we get
y = (x+2)*(x)*(x-3) = x^3 - x^2 - 6x
We graph the equation in the attached file.
Answer:
Step-by-step explanation:
I mean, you can divide the counters by the range 2 - 38.
I only managed to find out that 38 ÷ 2 = 19.
And 38 ÷ 19 = 2.
It says that there are more than 10 counters in each bag.
So 2 bags is the most liable option.
There are 2 bags and 19 counters in each bag.
Answer:
D
Step-by-step explanation:
Substitute the f(x) and g(x) into f/g
![\frac{\sqrt[3]{3x} }{5x+2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%7D%20%7D%7B5x%2B2%7D)
To find the domain,
Get the denominator of the fraction so 5x + 2 and equal it to 0 and find x
5x + 2 = 0
5x = -2
x = 
Therefore it's D