The answer is D
You just need to subtract term 1 (5) from term 2 (10) to find the answer, and the common difference between each sequential term is 5
Step-by-step explanation:
-8 - -4= -8+4=-4
16- -4=20
8- -4=12
-9--4=-5
Answer:
129/2
Step-by-step explanation:
1 129
64 --- = -------
2 2
To find the improper fraction, you multiply the denominator by the whole number and then add the numerator. In the end, you put that answer over the starting denominator.
64 X 2 = 128 128 + 1 = 129 129 / 2 is the answer
Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027
So you would do
5×4×3= 60
and
5×4=20
so, for a 3 digit code there are 60 possibilities and for a 2 digit code there are 20 possibilities.
