Question

I need help!!

Answer 1

Answer:

2x +21

Step-by-step explanation:

$log_{5} {5}^{(2x - 9)} + log_{3} {729}^{5} \\ \\ = log_{5} {5}^{(2x - 9)} + log_{3} {( {3}^{6} )}^{5} \\ \\ = log_{5} {5}^{(2x - 9)} + log_{3} { {3}}^{6 \times 5} \\ \\ = log_{5} {5}^{(2x - 9)} + log_{3} { {3}}^{30} \\ \\ =(2x - 9) log_{5} {5} + 30 log_{3} { {3}} \\ \\ = (2x - 9).1 + 30(1 )\\ ( \because \: log_{a} { {a}} = 1) \\ \\ = 2x - 9 + 30 \\ \\ = 2x +21$