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svetoff [14.1K]
3 years ago
6

Need help frl thank u

Mathematics
1 answer:
mr_godi [17]3 years ago
5 0

Answer:

the answer 180

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Loxlor<br><img src="https://tex.z-dn.net/?f=10%20%5Ctimes%2010" id="TexFormula1" title="10 \times 10" alt="10 \times 10" align="
Marina CMI [18]

Answer:

Step-by-step explanation:

10 in 10 places is 100. 10*1=10. 10*2=20..10*3=30.10*4=40,. 10*5=50,10*6=60,,,10*7=70,,. 10*8=80,. 10*9=90,. 10*10=100.

8 0
3 years ago
Solve for x. Thank you.
Bas_tet [7]

Answer:

D) 50/3

Step-by-step explanation:

6/10 = 10/(6+x-6)

6/10 = 10/x

6x = 100

 x = 100/6

 x = 50/3

4 0
3 years ago
Which choice is equivalent to the expression below?
Andre45 [30]

<u>Answer:</u>

C. 4\sqrt{7} -4x\sqrt{7} is correct

<u>Steps</u><u>:</u>

4\sqrt{7} -3\sqrt{7}x-x\sqrt{7} \\\\4\sqrt{7} -3\sqrt{7} x-\sqrt{7} x\\\\4\sqrt{7} +(-3\sqrt{7} x-\sqrt{7} x)\\\\4\sqrt{7} -4\sqrt{7} x

7 0
3 years ago
Read 2 more answers
A waitress sold 12 ribeye steak dinners and 39 grilled salmon totaling $575.53 on a particular day. Another day she sold 25 ribe
DedPeter [7]

Answer:

The cost of a ribeye steak dinner is $18.60.

The cost of a grilled salmon dinner is $9.03.

Step-by-step explanation:

let r be the cost of a ribeye steak dinner

let g be the cost of a grilled salmon dinner

Represent the two situations using equations:

12r + 39g = 575.53   (equation 1)

25r + 13g = 582.43   (equation 2)

The best method to use for this case is elimination, which is when you get rid of one of the variables by subtracting or adding.

Since the coefficients for "g" are 39 and 13, they can be eliminated if equation 2 was triple itself.

(25r + 13g = 582.43)  X 3

= 75r + 39g = 1747.29  (new equation 2)

Subtract "equation 1" from "new equation 2"

.   75r + 39g = 1747.29

<u>-   12r + 39g = 575.53</u>

.    63r + 0g = 1171.76    <=we only deal with "r" because 0g is nothing

.             63r = 1171.76    <=divide both sides by 63 to isolate r

.                 r = 18.60       <=rounded from 18.599...

The cost of a ribeye steak dinner is $18.60.

Use any one of the equations to solve for "g", the cost of grilled salmon dinners. I will use equation 1.

12r + 39g = 575.53

Substitute r = 18.6

12(18.6) + 39g = 575.53   <=only one variable now

223.2 + 39g = 575.53     <=subtract 223.2 from both sides

39g = 352.33             <=divide both sides by 39 to isolate g

g = 9.03  <=rounded from 9.0341...

The cost of a grilled salmon dinner is $9.03.

4 0
3 years ago
I NEED HELP ASAP PLEASE!!!
Alex17521 [72]

Answer:

Q2: -17

Q3: a) -5/2  b) g = -13

Step-by-step explanation:

2w+7 = -9

2w = -9 - 7

w = -16/2

w = -8

---

15 - 4w

= 15 - 4(-8)

= 15 - 32

= -17

----------------------

Q3:

a) 3/4(16m-24) = -48

16m -24 = -48 ÷ 3/4

16m = -64 + 24

16m = -40

m = -5/2

b) -20 = 1/6(36+12g)

-20 = 1/6 × 6(6+2g)

(cross out the 6 from 1/6 and 6)

-20 = 6 + 2g

-20-2g= 6

-2g = 6+20

-2g = 26

g = 26/-2

g = -13

3 0
3 years ago
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