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topjm [15]
3 years ago
5

Put the following numbers in order from smallest to largest.

Mathematics
2 answers:
rosijanka [135]3 years ago
8 0

Step-by-step explanation:

the order in which you asked the question is correct

ira [324]3 years ago
7 0

Answer: 4.01, 4.1, 40.1, 41

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Which shows the rational expression written using the least common denominator?x-2/x^3
Gelneren [198K]

Answer:

Multiply 2/3 and your number. If you have a whole number, convert it to a fraction by putting it over a denominator of 1. When multiplying fractions, calculate numerator times numerator, then denominator times denominator. For example, to find two-thirds of 18, multiply 2/3 x 18/1 to get 36/3.

6 0
3 years ago
Which function represents a translation of the graph of v=x^2
KatRina [158]

Answer:

B.

Step-by-step explanation:

That would be y = (x +10)^2.

8 0
2 years ago
Write the phrase as a rate in simplest form. $406 for 38 pieces
Anna71 [15]

Answer:

Rate will be $10.68/-

Step-by-step explanation:

For 38 pieces we have price $406

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The rate will be $10.68/-

6 0
3 years ago
Read 2 more answers
What’s 5/10 + 1/3 I really need help
kap26 [50]
5/10 + 1/3

15/30 + 10/30 = 25/30 = 5/6

Answer : 5/6 in its simplified form
7 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Katena32 [7]

Answer:

(a)

5^{-3}=\frac{1}{125}

(b)

-5^{-3}=-\frac{1}{125}

(c)

(-5^{-3})^{-1}=-125

(d)

(-5^{-3})^{0}=1

Step-by-step explanation:

(a)

5^{-3}

we can use property of exponent

a^{-n}=\frac{1}{a^n}

we get

5^{-3}=\frac{1}{5^3}

5^{-3}=\frac{1}{5\times 5\times 5}

5^{-3}=\frac{1}{125}........Answer

(b)

-5^{-3}

we can use property of exponent

a^{-n}=\frac{1}{a^n}

we get

-5^{-3}=-\frac{1}{5^3}

-5^{-3}=-\frac{1}{5\times 5\times 5}

-5^{-3}=-\frac{1}{125}........Answer

(c)

(-5^{-3})^{-1}

we can use property of exponent

(a^{n})^m=a^{m\times n}

we get

(-5^{-3})^{-1}=(-5)^{-3\times -1}

(-5^{-3})^{-1}=(-5)^3

(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)

(-5^{-3})^{-1}=-125........Answer

(d)

(-5^{-3})^{0}

we can use property of exponent

(a^{n})^m=a^{m\times n}

we get

(-5^{-3})^{0}=(-5)^{-3\times 0}

(-5^{-3})^{-1}=(-5)^0

we can use property

a^0=1

(-5^{-3})^{0}=1........Answer

4 0
3 years ago
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