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Varvara68 [4.7K]
3 years ago
6

Only about 50% of the solar energy directed toward Earth penetrates directly to the surface. Explain what happens to the rest of

the radiation.
Physics
2 answers:
Hoochie [10]3 years ago
6 0

Answer:

A. It is absorbed or reflected by the atmosphere.

Explanation:

I did the test

Tresset [83]3 years ago
4 0

Answer:

it is absorbed or reflected by the atmosphere

Explanation:

In the case when approx 50% only of the solar energy would be directed towards earth and it would be penetrates directly to the surface so the rest or remaining of the radiation would be either absorbed or refected by the atmosphere

So as per the given situation the above represent the answer

hence, the same is to be considered and relevant

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Two stars of masses M and 6M are separated by a distance D. Determine the distance (measured from M) to a point at which the net
kotykmax [81]

Answer:

0.29D

Explanation:

Given that

F = G M m / r2

F = GM(6m) / (D-r)2

G Mm/r2 = GM(6m) / (D-r)2

1/r2 = 6 / (D-r)2

r = D / (Ö6 + 1)

r = 0.29 D

See diagram in attached file

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3 years ago
Why is photosynthesis essential for plant homeostasis?
aalyn [17]
It should be answer choice b
6 0
3 years ago
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Please help on this one?
ruslelena [56]

Answer:

A, 30V

Explanation:

First combine all resistors to an equivalent resistor. Since they are in series, the equivalent resistance is the sum of all resistor

Req = 20 + 40 + 60 = 120Ω

Using Ohm's law, find the current in the circuit

V = I * R

I = V / R

I = 60V / 120Ω

I = 0.5 A

Now the potential drop across the resistor R3 is the current times R3 resistance, therefore:

Vdrop = 0.5A * 60Ω = 30V

So the potential drop across resistor R3 is 30 V

3 0
3 years ago
Read 2 more answers
Why is the wavelength of a moving soccer ball not detectable to the naked eye?
Blababa [14]

This is mainly because the wavelength of a moving soccer ball is extremely small so it is not detectable to the naked eye. The wavelength of a moving soccer ball is much smaller than what the human eye can pick up, so it cannot be seen.

3 0
3 years ago
What is the magnitude and direction of an electric field that exerts a 2.00×10−5N upward force on a –1.75μC charge?
Sophie [7]

Answer:

E = - 11.4 N/C, Directed Downward

Explanation:

Force = 2.00×10⁻⁵N , charge Q = –1.75μC = -1.75 ×10⁻⁶ C

To Find: Electric Field E = ? and Direction=?

Sol

we Have

E = F / Q

E = 2.00×10⁻⁵N /  -1.75 ×10⁻⁶ C

E = - 11.428 N/C (-ve sign shows that it is Negative Electric Field around a negative charge and will attract the Positive Field)

As given an upward force on negative charge so direction of the Electric Filed will be Downward (as Electric field is opposite to direction of force on negative charge)

3 0
3 years ago
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