The oxidation state, sometimes referred to as oxidation number, describes the degree of oxidation of an atom in a chemical compound.
<u>Explanation:</u>
The oxidation number of an atom is the charge that atom would have if the compound was composed of ions. 1. The oxidation number of an atom is zero in a neutral substance that contains atoms of only one element. The oxidation number of simple ions is equal to the charge on the ion.
The oxidation number of a mono atomic ion equals the charge of the ion. The oxidation number of H is +1, but it is -1 in when combined with less electro negative elements. The oxidation number of O in compounds is usually -2, but it is -1 in peroxides. The oxidation number of a Group 1 element in a compound is +1.
Answer:
The hydroxyl group
Explanation:
The molecular formulas of the above alcohols are
CH₃CH₂-OH
CH₃CH₂CH₂CH₂CH₂CH₂CH₂CH₂-OH
CH₃-OH
CH₃CH(CH₃)CH₂CH₂-OH
The functional group that is characteristic of all alcohols is the hydroxyl group (-OH).
Answer:
45.3°C
Explanation:
Step 1:
Data obtained from the question.
Initial pressure (P1) = 82KPa
Initial temperature (T1) = 26°C
Final pressure (P2) = 87.3KPa.
Final temperature (T2) =.?
Step 2:
Conversion of celsius temperature to Kelvin temperature.
This is illustrated below:
T(K) = T(°C) + 273
Initial temperature (T1) = 26°C
Initial temperature (T1) = 26°C + 273 = 299K.
Step 3:
Determination of the new temperature of the gas. This can be obtained as follow:
P1/T1 = P2/T2
82/299 = 87.3/T2
Cross multiply to express in linear form
82 x T2 = 299 x 87.3
Divide both side by 82
T2 = (299 x 87.3) /82
T2 = 318.3K
Step 4:
Conversion of 318.3K to celsius temperature. This is illustrated below:
T(°C) = T(K) – 273
T(K) = 318.3K
T(°C) = 318.3 – 273
T(°C) = 45.3°C.
Therefore, the new temperature of the gas in th tire is 45.3°C
Answer:
5.2 moles of KClO₃ are needed
Explanation:
Given data:
Number of moles of potassium chlorate needed = ?
Number of moles of O₂ formed = 7.8 mol
Solution:
Chemical equation:
2KClO₃ → 2KCl + 3O₂
now we will compare the moles of KClO₃ and O₂.
O₂ : KClO₃
3 : 2
7.8 : 2/3×7.8 = 5.2
5.2 moles of KClO₃ are needed.
