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const2013 [10]
3 years ago
13

Write the balanced dissociation equation for solid sulfur difluoride in aqueous solution. If it does not dissociate, simply writ

e only NR.
Chemistry
1 answer:
mojhsa [17]3 years ago
3 0

Answer:

SF2(aq) → S²⁺(aq) + 2F-(aq)

Explanation:

The sulfur difluoride, SF2, dissolves in water because the differences in electronegativities are considerable (3.98 for Fluorine and 2.58 for S) doing the F-S bond polar. As water is a polar solvent will dissolve the SF2 as follows:

<h3>SF2(aq) → S²⁺(aq) + 2F-(aq)</h3>

<em>As Fluorine has a > electronegativity than S, the Fluorine will be negative and S will be positive. Also, all halogen ions has a charge of -1.</em>

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Which statement about Schrödinger's theory of the atomic model is true?
vekshin1

Answer : Option C) It explained the odds of finding the position of an electron.

Explanation : Schrödinger's theory of the atomic model is true for the probability of finding the electron around the nucleus. Schrödinger used odd mathematical equations to describe the likelihood of finding an electron in a certain position around the nucleus. This atomic model was known as the quantum mechanical model of the atom. He posed an equation which is now called as the Schordinger’s Wave Equation, which incorporates both the wave-like and particle-like behaviors of electrons, which stated that electrons can act like waves/light and particles. Which later helped to develop the uncertainty principle for finding the probable position of the electron.

4 0
4 years ago
if you drop a 50 gram piece of metal with a temperature of 125° Celsius into 1000 grams of water at 20° Celsius, what best descr
Ymorist [56]
As soon as the metal gets into the water a temperature transfer will start between both of them resulting in  

1. Metal will cool down. 
2. Some water will get evaporated.
3. Temperature of water will rise.
4. As the metal gets into the water, a sound like chissssss will be heard.

Hope it helps.
Don't be shy and say thx.<span />
8 0
3 years ago
20 mL of an approximately 10% aqueous solution of ethylamine, CH3CH2NH2, is titrated with 0.3000 M aqueous HCl. Which indicator
Vinvika [58]

20 mL of an approximately 10% aqueous solution of ethylamine, CH3CH2NH2, is titrated with 0.3000 M aqueous HCl. Which indicator would be most suitable for this titration? The pKa of CH3CH2NH3+ is 10.75.

Answer:

Bromocresol green, color change from pH = 4.0 to  5.6

Explanation:

The equation for the reaction is as follows:

C_2H_5NH_{2(aq)     +     H^+_{(aq)      ⇄        C_2H_5NH_{3(aq)}^+

Given that concentration of C_2H_5NH_{2(aq) = 10%

i.e 10 g of C_2H_5NH_{2(aq) in 100 ml solution

molar mass = 45.08 g/mol

number of moles = \frac{10}{45.08}

= 0.222 mol

Molarity of C_2H_5NH_{2(aq) = 0.222 × \frac{1000}{100}mL

= 2.22 M

However, number of moles of C_2H_5NH_{2(aq) in 20 mL can be determined as:

number of moles of C_2H_5NH_{2(aq) = 20 mL × 2.22 M

= 44*10^{-3} mole

Concentration of C_2H_5NH_{2(aq) = \frac{44*10^{-3}*1000}{20}

= 2.22 M

Similarly, The pKa Value of C_2H_5NH_{2(aq)  is given as 10.75

pKb value will be: 14 - pKa

= 14 - 10.75

= 3.25

Finally, the pH value at equivalence point is:

pH= \frac{1}{2}pKa - \frac{1}{2}pKb-\frac{1}{2}log[C]

pH = \frac{14}{2}-\frac{3.25}{2}-\frac{1}{2}log [2.22]

pH = 5.21

∴

The indicator that is best fit for the given titration is Bromocresol Green Color change from pH between 4.0 to 5.6.

6 0
4 years ago
If the lead concentration in water is 1 ppm, then we should be able to recover 1 mg of lead from _____ L of water.
Aliun [14]

Answer:

1 L

Explanation:

ppm means parts per million. Generally the relationship between mass and litre is given as;

1 ppm = 1 mg/L

This means that 1 ppm is equivalent to 1 mg of a substance dissolved in 1 L of water.

3 0
4 years ago
Determine the molar solubility of pbso4 in pure water. ksp (pbso4) = 1.82 × 10-8.
OLga [1]
When PbSO₄ is added it dissociates as follows
PbSO₄ --> Pb²⁺ + SO₄²⁻
molar solubility is the number of moles of solute that can be dissolved in 1 L of solution 
if molar solubility of PbSO₄ is X, then molar solubility of Pb²⁺ is X and SO₄²⁻ is X
the formula for ksp is as follows 
ksp - solubility product constant
ksp = [Pb²⁺][SO₄²⁻]
ksp = X * X 
ksp = X²
ksp = 1.82 x 10⁻⁸ 
X² = 1.82 x 10⁻⁸ 
X = 1.35 x 10⁻⁴ M
molar solubility of PbSO₄ is 1.35 x 10⁻⁴ M
answer is b.
3 0
4 years ago
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