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const2013 [10]
3 years ago
13

Write the balanced dissociation equation for solid sulfur difluoride in aqueous solution. If it does not dissociate, simply writ

e only NR.
Chemistry
1 answer:
mojhsa [17]3 years ago
3 0

Answer:

SF2(aq) → S²⁺(aq) + 2F-(aq)

Explanation:

The sulfur difluoride, SF2, dissolves in water because the differences in electronegativities are considerable (3.98 for Fluorine and 2.58 for S) doing the F-S bond polar. As water is a polar solvent will dissolve the SF2 as follows:

<h3>SF2(aq) → S²⁺(aq) + 2F-(aq)</h3>

<em>As Fluorine has a > electronegativity than S, the Fluorine will be negative and S will be positive. Also, all halogen ions has a charge of -1.</em>

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always contains the same proportions of atomic components.

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