Answer:
96.1 grams of percent yield
Answer:b
Explanation:
From the question, the stoichiometry of the balanced reaction equation showed that 180gof glucose give 134.4L of CO2. Then we are given to find the volume of carbon IV oxide given off by 126g of glucose. This is done as shown in the image by relating what is given to the stoichiometry of the balanced reaction equation to obtain the answer as shown.
Respiration. That is the process.
<span>1.006 g of Na2CO3 is left; which means that (2.714 -1.006) g of water are lost from the hydrated sodium carbonate
So, water present = </span>(2.714 -1.006) = 1.708 g.
Molecular Wt. of water is =18 g
so moles = 1.708/18 moles = 0.095 moles.
Now, <span>Na2CO3 has molecular wt. of = 23x2 + 12 +3x16 = 106 g,
so moles of Na2CO3 = 1.006/106 moles = 0.0095 moles </span>
<span>Ratio is = 0.0095 / 0.095 = 1 / 10 [ moles of Na2CO3 / moles of H2O ]
Ratio is saying on every 1 mole of Na2CO3 , there are 10 moles of H2O
so x is 10</span>
Answer:
0.032 mole
Explanation:
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