Answer:
The atomic mass (mₐ or m) is the mass of an atom. Although the SI unit of mass is the kilogram (symbol: kg), atomic mass is often expressed in the non-SI unit atomic mass unit (AMU) or unified mass (u) or dalton (symbol: Da), where 1 AMU or 1 u or 1 Da is defined as 1⁄12 of the mass of a single carbon-12 atom, at rest. The protons and neutrons of the nucleus account for nearly all of the total mass of atoms, with the electrons and nuclear binding energy making minor contributions.
1 mole of H2O weighs 18 g
therefore 13.8 g of liquid H2O = 13.8/18 moles
ΔHvaporization = 40.65 kJ/mol
heat required to change 13.8 grams of H2O from a liquid to a gas at 100 degrees Celsius = 40.65 x 13.8/18 = 31.165 kJ
Answer:
The bands are due to:
λmax = 289 nm n→π* transition (E = 12)
λmax = 182 nm π→π* transition (E=10000)
Explanation:
The two types of acetaldehyde transition are as follows:
n→π* and π→π*
From the attached diagram we have to:
ΔEn→π* < ΔEπ→π*
ΔEα(1/λ)
Thus:
λn→π* > λπ→π*
In n→π* spin forbidden, the intensity is low. Thus, the molar extinction E for n→π* is very low.
The same way, for π→π* spin allowed the intensity is high. Thus, the molar extinction coefficient E for π→π* is high too.
The bands are due to:
λmax = 289 nm n→π* transition (E = 12)
λmax = 182 nm π→π* transition (E=10000)
The phylogeny of an organism is its evolutionary history.
To solve for moles use molar and volume:
M = mol/L
0.02700 m= mol/(.75 L)
mol = .036 mol of Hg(NO3)2
The proportion of Hg(NO3)2 to the Mercury that is used to create
HgS is 1:1 so solve for the moles of Mercury used. So:
.036 * (1 Hg(NO3)2 / 1 Hg) = .036 moles of Hg used to make
HgS
The proportion of Mercury to HgS is 1:1, as an alternative
of doing the obvious math you can conclude that .036 moles of HgS will be
produced because you're given .036 moles of Hg and an excess of S. Use the
molar mass of HgS to determine how many grams will be produced.
.036 moles * 232.66 g/mol = 8.37576 grams of Vermilion is
produced.
