Vermilion, a very rare and expensive solid natural pigment that has been used to print artists' signatures on works of art, is m
ercury(ii) sulfide. what mass of vermilion can be produced when 75.0 ml of 0.02700 m mercury(ii) nitrate is mixed with a solution containing excess sodium sulfide? vermilion is insoluble in water.
The proportion of Hg(NO3)2 to the Mercury that is used to create
HgS is 1:1 so solve for the moles of Mercury used. So:
.036 * (1 Hg(NO3)2 / 1 Hg) = .036 moles of Hg used to make
HgS
The proportion of Mercury to HgS is 1:1, as an alternative
of doing the obvious math you can conclude that .036 moles of HgS will be
produced because you're given .036 moles of Hg and an excess of S. Use the
molar mass of HgS to determine how many grams will be produced.
.036 moles * 232.66 g/mol = 8.37576 grams of Vermilion is
produced.
In the qualitative analysis of metal salts , we see that in group I , metal chlorides are precipitated out . It is so because their metal chlorides are insoluble in water .
