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Mashutka [201]
3 years ago
6

Encuentra la ecuacion de la parabola con vertice en el origen y foco en las cordenadas 0,1en su forma ordinaria y general

Mathematics
1 answer:
marusya05 [52]3 years ago
5 0

Answer:

x^{2}=4y

y=\frac{1}{4}x^{2}

Step-by-step explanation:

Forma ordinaria

La ecuación de la parabola de manera ordinaria está dada por:

(x-h)^{2}=4p(y-k) (1)  

Donde:

  • (h,k) es la coordenda del vértice, en nuestro caso (0,0) ya que está en el origen.
  • (h,k+p) es la coordenda del foco, en nuestro caso (0,1).

Por lo tanto h = 0, k = 0 y p = 1.

Remplazando estos valores en la ecuación de la parábola, tenemos:

(x-0)^{2}=4*1(y-0)

x^{2}=4y (2)

 

Forma general  

La forma general de una parábola esta dada por la siquiente ecuación

y=ax^{2}+bx+c

Reordenando la ecuación (2) tenemos:

y=\frac{1}{4}x^{2}

Espero esto te haya ayudado!

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