All categories

3 years ago

Which of the following values for m proves that 2m + 2m is not equivalent to 4m2?

Mathematics

2 answers:

Mashutka [201]3 years ago

6 0

M=0 i am not sure it is right

max2010maxim [7]3 years ago

4 0

When m=0 ,

2m+2m=2(0)+2(0)= 0

$4m^{2}.=4(0^{2})=0$

When m=1 ,

2m+2m=2(1)+2(1)=2+2=4.

$4m^{2}. =4(1)^{2}.=4.$

When m=2

2m+2m=2(2)+2(2)=4+4=8.

$4m^{2}.=4(2)^{2}.=4(4)=16.$

Both expressions are not equivalent when m=2.

You might be interested in

Any help would be appreciated

vlabodo [156]

Answer:

$8.25

Step-by-step explanation:

I don't know how to explain it to you but if I'm wrong tell me I'll try it aagain.

7 0

2 years ago

The sum of two numbers is 20.8 and their difference os 10.2. Find these numbers.

Slav-nsk [51]

Answer:

the numbers are 10.6 and 10.2

6 0

3 years ago

Θ is in Quadrant III and cos^2 0= 1/4

pychu [463]

I think you mean to say $\cos^2\theta=\dfrac14$ . If $\theta$ is in the third quadrant, then $\sin\theta$ and $\cos\theta$ . Recall that

$\sin^2\theta+\cos^2\theta=1\implies\sin\theta=\pm\sqrt{1-\cos^2\theta}$

We expect $\sin\theta$ to be negative, so we take the negative root. We end up with

$\sin\theta=-\sqrt{1-\dfrac14}=-\dfrac{\sqrt3}2$

We also know to expect $\cos\theta$ , so

$\cos\theta=\pm\sqrt{\dfrac14}\implies\cos\theta=-\dfrac12$

By definition, we have

$\cot\theta=\dfrac{\cos\theta}{\sin\theta}$

and so

$\cot\theta=\dfrac{-\frac12}{-\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

7 0

3 years ago

Parker drove a total distance of 4 and 1 over 2 miles during the months of June and July. If Parker only drove 1 over 8 of a mil

never [62]

Answer: 4 and 1 over 2 ÷ 1 over 8

Step-by-step explanation:

Given that : Total distance drove by Parker =4 and 1 over 2 miles= $4\frac{1}{2}$ miles