Which of the following values for m proves that 2m + 2m is not equivalent to 4m2?

Mathematics

2 answers:

Mashutka [201]2 years ago

6 0

M=0 i am not sure it is right

max2010maxim [7]2 years ago

4 0

When m=0 ,

2m+2m=2(0)+2(0)= 0

$4m^{2}.=4(0^{2})=0$

When m=1 ,

2m+2m=2(1)+2(1)=2+2=4.

$4m^{2}. =4(1)^{2}.=4.$

When m=2

2m+2m=2(2)+2(2)=4+4=8.

$4m^{2}.=4(2)^{2}.=4(4)=16.$

Both expressions are not equivalent when m=2.

You might be interested in

a rectangular table is two times as long as it is wide. if the area is 18ft^2, find the length and the width of the table.

Tasya [4]

Start here: A = 18 ft^2 = L * W. Next, L = 2W.

Merging these 2 formulas lets us eliminate L:

18 ft^2 = (2W) * (W) = 2W^2.

So W^2 = 9 ft^2, and W=3 ft. Please use L = 2W (from above) to calculate L.

4 0

2 years ago

Josie can solve 4/3 rubix cubes in 1/6 of an hour. How many rubix cubes can she solve an in hour please help

777dan777 [17]

Answer:

Step-by-step explanation:

So 1/6 of an hour is 10 minutes and 3/4 of a Rubiks cube is technically 1 1/4 so in an hour she can solve five in an hour

3 0

2 years ago

Area triangles? it says show work so pls do

coldgirl [10]

$\large{\underline{\underline{\pmb{\sf {\color {blue}{Solution:}}}}}}$

Given,

Area = 225 yd²

Base = 30 yd

Height = [To be calculated]

To find:

The height of the given triangle.

We know that, area of a triangle is:

$\frac{1}{2} \times (b \times h) \\ \\ \leadsto \frac{1}{2} \times (30 \times h) \\ \\ \leadsto \frac{1}{2} \times 30h \\ \\ \leadsto \frac{1}{ \cancel{2}} \times \cancel{30}h \\ \\ \leadsto1 \times 15h \\ \\ \leadsto \: h = 15 \: yd$

Therefore, the require height is 15 yd.

$\green\star$ Proof:

$\frac{1}{2} \times (b \times h) \\ \\ \leadsto \frac{1}{2} \times (30 \times 15) \\ \\ \leadsto \frac{1}{ \cancel{2}} \times \cancel{450} \\ \\ \leadsto1 \times 225 \\ \\ area = 225 {yd}^{2}$