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Naya [18.7K]
3 years ago
8

Find n(a) for the set

Mathematics
1 answer:
elixir [45]3 years ago
6 0

Answer:

11

Step-by-step explanation:

n(A) means the number of elements in set A

Element 1=-10

Element 2=-9

Element 3=-8

Follow the pattern

Element 4=-7

Element 5=-6

Element 6=-5

Element 7=-4

Element 8=-3

Element 9=-2

Element 10=-1

Element 11=0

There are 11 elements in set A.

Also this has the same number of elements as {0,1,2,...,8,9,10} which has (10+1) elements.

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Solve for x in simplest form.<br>14 = 1/3(8x + 6)​
elena-s [515]

Answer:

x = 4.5

Step-by-step explanation:

14 = 8/3x + 2

12 = 8/3x

36 = 8x

x = 4.5

5 0
3 years ago
T a linen sale Mrs. Earle bought twice as many pillowcases for $2 each as sheets for $5 each. If she spent less than $40, not in
Anettt [7]
For this case, the first thing we must do is define variables:
 x: number of pillowcases
 y: number of sheets
 We now write the system of equations:
 2x + 5y = 40
 x = 2y
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 x = 8.9
 y = 4.4
 Answer:
 
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3 0
3 years ago
There are 49 dogs signed up for a dog show. There are 36 more small dogs than the large dogs. How many small dogs have signed up
mixer [17]

Answer:

I think it is 41.5...

3 0
2 years ago
If 12 cars are needed o get 36 students to the end of the road with their packs, how many cars will be able to carry 9 students
Alina [70]

Answer:

3 cars

Step-by-step explanation:

If 12 cars are needed to carry 36 students,

<em>12</em><em>c</em><em>a</em><em>r</em><em>s</em><em> = 36</em>

the number of cars to carry 9 students will be:

xcars = 9

cross the two equations

36x = 12 X 9

36x = 108

x = 108/36

x= 3

Therefore, 3 cars are needed to carry 9 students

OR

12 cars will carry 36 students

so 1 car will carry, (36/12)students

therefore, 1 car will carry 3 students

So, for 9 students,

9students = 9/3 = 3

7 0
3 years ago
Read 2 more answers
Please help me answer this. I think that for the first one the answer is A, but I am not sure. There are two parts to the questi
Anika [276]
Vector PQ=(7-5, 3-4)=(2, -1).  4RS=4 \cdot (4-8, 1-6) = 4 \cdot (-4, -5) = (-16, -20).  So the sum is (-14, -21).

For the second, the magnitude is the square root of the sum of the squares of the components.  This is equal to \sqrt{(-14)^2+(-21)^2} = \sqrt{637}=7\sqrt{13}.
4 0
3 years ago
Read 2 more answers
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