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3 years ago

Find n(a) for the set

Mathematics

1 answer:

elixir [45]3 years ago

6 0

Answer:

Step-by-step explanation:

n(A) means the number of elements in set A

Element 1=-10

Element 2=-9

Element 3=-8

Follow the pattern

Element 4=-7

Element 5=-6

Element 6=-5

Element 7=-4

Element 8=-3

Element 9=-2

Element 10=-1

Element 11=0

There are 11 elements in set A.

Also this has the same number of elements as {0,1,2,...,8,9,10} which has (10+1) elements.

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Each month, 8 magazines arrive at Sydney's home. Write an equation that would show the number of motnths (n) it took for Sydney

Dovator [93]

C.
Since 8 magazines are areiving each month (n) and the total is 56, all you have to do is multiply 8 by n and you get 56, the actual answer would be 7 though.

7 0

3 years ago

A rectangular box has the dimensions shown in the diagram. The volume of the box is given by the function V(x) = x3 – 4x, where

marta [7]

Answer:

$Height =3$

Step-by-step explanation:

Given

$Length = x + 2$

$Width = x - 2$

$Height = x$

$Volume = 15$

Required

Find the height

The volume is calculated as thus:

$Volume = Length * Width * Height$

This gives

$15 = (x + 2) * (x - 2) * x$

Apply difference of two squares

$15 =(x^2 - 4 ) * x$

$15 = x^3 - 4x$

Subtract 15 from both sides

$x^3 - 4x - 15 = 0$

Using a calculator to factorize, we have:

$(x-3)(x^2+3x+5) = 0$

Split

$x - 3 = 0$ or $x^2 + 3x + 5 = 0$

$x = 3$ or $x^2 + 3x + 5 = 0$

x has complex roots for $x^2 + 3x + 5 = 0$

Hence:

$x = 3$

Recall that:

$Height = x$

$Height =3$

3 0

3 years ago

What is the answer to this I really need the answer for my test 8/9+2/3+1/6

ElenaW [278]

The all go over 18 so put them all over 18
16/18+12/18+3/18=31/18

31/18 or 1.722222222........

8 0

3 years ago

Read 2 more answers

I really really really need help!!!!

Yakvenalex [24]

For $f$ to be continuous at $x=1$ , you need to have the limit from either side as $x\to1$ to be the same.

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^-}(|x-1|+2)=2$
$\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1^+}(ax^2+bx)=a+b$

If $a=2$ and $b=3$ , then the limit from the right would be $2+3=5\neq2$ , so the answer to part (1) is no, the function would not be continuous under those conditions.

This basically answers part (2). For the function to be continuous, you need to satisfy the relation $a+b=2$ .

Part (c) is done similarly to part (1). This time, you need to limits from either side as $x\to2$ to match. You have

$\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2^-}(ax^2+bx)=4a+2b$
$\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2^+}(5x-10)=0$

So, $a$ and $b$ have to satisfy the relation $4a+2b=0$ , or $2a+b=0$ .

Part (4) is done by solving the system of equations above for $a$ and $b$ . I'll leave that to you, as well as part (5) since that's just drawing your findings.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=3%20%5Csqrt%7B50%7D%20%20%5Ctimes%20%20%5Csqrt%7B22%7D%20" id="TexFormula1" title="3 \sqrt{50}

wariber [46]

Answer:I'm 97.248316478692% sure it's C.

Step-by-step explanation:

6 0

3 years ago