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3 years ago

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Suppose two acid solutions are mixed. One is 26% acid and the other is 34% acid. Which one of the following concentrations canno

t possibly be the concentration of the mixture? a) 24% b) 30% c) 31% d) 33%

1 answer:

valentina_108 [34]3 years ago

7 0

Answer:

A

Step-by-step explanation:

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Hi please answer and you dont NEED to show work but if u do i will give brainliest

Advocard [28]

Answer:

$y=-\frac{2}{5} -1$

Step-by-step explanation:

So first thing is that slope intercept form is setup like this

y=mx+b

m=slope

b=y intercept

the slope is change in y over change in x

as y goes down 2 x goes up 5

so the slope is -2/5

the y intercept is at (0,-1) so the y intercept is -1

therefore the answer is

$y=-\frac{2}{5} -1$

have a great day :)

8 0

3 years ago

Read 2 more answers

I need the answer. Please help.

Marysya12 [62]

Using the Pythagorean theorem:

WY =√(5^2 + 12^2)

WY = √(25 +144)

WY = √169

WY = 13 mm

7 0

3 years ago

An object travels along a circular path so that it completes one revolution in 8 seconds. If the linear velocity of the object i

natima [27]

Answer:

Using the concept of speed-distance-time, we find that the diameter of the circular path is 12 inches.

Step-by-step explanation:

Given that the object completes one revolution in 8 seconds. So, the circular speed of the object is 2πr/8 = πr/4 inches per seconds, where r is the radius of the circular path. The speed can be written as:

πr/4 inches per seconds = 60πr/4 inches per minute = 15πr inches per minute.

But, it is given that the circular speed of the object is 90π inches per minute. So,

90π = 15πr

r = 6 inches

Since, diameter is the double of radius, d = 2r = 12 inches.

For more explanation, refer the following link:

brainly.com/question/17978382

#SPJ10

4 0

2 years ago

25 lb greater or less than 384 oz

NeTakaya

25 lbs would be greater than 384 oz because 384 divided by 16 (because 16 oz per lb) =24lbs
so 25lbs > 384 oz

7 0

3 years ago

Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.

Lelechka [254]

Answer:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}} = 32$

Step-by-step explanation:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}$

Solving using exponent rule: $a^{-m}=\frac{1}{a^m}$

$\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32$

So, $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4}$

Using the exponent rule: $a^m.a^n=a^{m+n}$

We have:

$2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}$

We also know that: $a^{-m}=\frac{1}{a^m}$

Using this rule:

$2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}$

So, $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2$

Solving:

$(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}$

So, $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}}$

We know that: $a^{-m}=\frac{1}{a^m}$

$\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32$

So, $\frac{2}{2^{-4}} = 32$

3 0

3 years ago