I know what the answer is
So this is a two step process, first you must find the area of the rectangle, then find the area of the semicircle.
So to find the area of a rectangle, you use: Length*Height=Area
In this case that would be: 7*2=14cm
Next you find the area of the semicircle, to do this you first find the area of the circle (Pi*r^2) then divide it by 2.
The diameter of the circle is 4 because: 7-2-1=4cm
Next divide that by 2 so that you get the radius: 4/2=2cm
Not you can plug that into the equation to get the area of the circle: Pi*2^2<span>≈13cm^2
Next divide it by 2 so that you get the area of the semicircle:13/2</span><span><span>≈</span>6cm^2
At this point you can add the area of the semicircle to the area of the rectangle: 14+6=20cm^2
So your final answer is 20cm^2!
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You have to divide the number by the denominator of the fraction. For example, if you want to find 1/5 of 20, you have to divide 20 by 5 and that tells you that 1/5 of 20 is 4.
Check the picture below.
so the shape is really 4 triangles with a base of 2 and a height of 4 each, and 2 squares tha are 4x4.
![\bf \stackrel{\textit{area of the 4 triangles}}{4\left[\cfrac{1}{2}(2)(4) \right]}~~+~~\stackrel{\textit{area of the two squares}}{2(4\cdot 4)}\implies 16+32\implies 48](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%204%20triangles%7D%7D%7B4%5Cleft%5B%5Ccfrac%7B1%7D%7B2%7D%282%29%284%29%20%5Cright%5D%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20two%20squares%7D%7D%7B2%284%5Ccdot%204%29%7D%5Cimplies%2016%2B32%5Cimplies%2048)
Answer:
b
Step-by-step explanation:
4 2/3= 12/3+2/3=14/3
3 2/1=7/2 but you have to flip it
so you end up with 14/3*2/7
