Question

Simplify (sin^2 0+cos^2 0) (sin 0+cos 0) Can someone help? I don’t understand.

Answer 1

Answer:

C) $sin\theta+cos\theta$

Step-by-step explanation:

$(sin^2\theta+cos^2\theta)(sin\theta+cos\theta)$

$sin\theta+cos\theta$

Recall the Pythagorean Trigonometric Identity where $sin^2\theta+cos^2\theta=1$, so $1(sin\theta+cos\theta)=sin\theta+cos\theta$

Answer 2

Answer:

C

Step-by-step explanation:

To start this problem off, we should know an important trig rule:

$\sin^2(\theta)+\cos^2(\theta)=1$

From here, it is simple:

$(\sin^2(\theta)+\cos^2(\theta))(\sin(\theta)+\cos(\theta))=\\1(\sin(\theta)+\cos(\theta))=\\\sin(\theta)+\cos(\theta)$

C

I hope this helps! Let me know if you have any questions :)