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Korolek [52]
3 years ago
11

Please help asap i am timed will give brainliest

Mathematics
1 answer:
wariber [46]3 years ago
4 0

Answer

Step-by-step explanation:

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Circle X is shown. Points W, Y, and Z are on the circle. Lines are drawn through each point on the circle.
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Answer:

Its point X

Step-by-step explanation:

Just did it on edge 2020

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Suppose that poaching reduces the population of an endangered animal by 6​% per year. Further suppose that when the population o
artcher [175]

If poaching reduces the population of an endangered animal by 6% and the criteria of population extinction is 20 with present population 1500 then it will take 3.62 years to reach to the mark of extinction.

Given Poaching reduces the population of endangered animals by 6% per year. The criteria of population extinction is 20. Present population being 1500.

Number of years taken by the population of endangered animals to reach to 20 mark can be calculated as under:

20=1500*(1-0.06)^{n}

20=1500*0.94^{n}

20/1500=0.94^{n}

0.133=0.94^{n}

take log both sides

log(0.133)=log0.94^{n}-------1

log(0.133)=nlog (0.94)

put the values log values:

log(0.133)=-0.8761

log(0.94)=-0.0268

Taking 1

-0.8761=n*(-0.0268)

n=0.8761/0.0268

n=3.269

Hence to reach level of 20 the population takes 3.2 years.

Learn more about logarithm at brainly.com/question/25710806

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2 years ago
What is the sum of (x - 8) - (2x + 2)
Dahasolnce [82]

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the answer is 4

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The total stopping distance T for a vehicle is T = 2.5x + 0.5x 2 , where T is in feet and x is the speed in miles per hour. Appr
Kobotan [32]

Answer:

%  change in stopping distance = 7.34 %

Step-by-step explanation:

The stooping distance is given by

T = 2.5 x + 0.5 x^{2}

We will approximate this distance  using the relation

f (x + dx) = f (x)+ f' (x)dx

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T' =  2.5 + x

Therefore

f(x)+f'(x)dx = 2.5x+ 0.5x^{2} + 2.5 +x

This is the stopping distance at x = 25

Put x = 25 in above equation

2.5 × (25) + 0.5× 25^{2} + 2.5 + 25 = 402.5 ft

Stopping distance at x = 25

T(25) = 2.5 × (25) + 0.5 × 25^{2}

T(25) = 375 ft

Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft

%  change in stopping distance = \frac{27.5}{375} × 100

%  change in stopping distance = 7.34 %

6 0
3 years ago
????????????????????????????
frutty [35]

Answer:

B

Step-by-step explanation:

i took the same question hope this helps :D

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