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3 years ago

A sample of sulfur dioxide (SO2) is initially at a temperature of

Chemistry

1 answer:

creativ13 [48]3 years ago

8 0

Answer:

874.89 mmHg

Explanation:

Using the combined gas law equation as follows:

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (mmHg)

P2 = final pressure (mmHg)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

Based on the information provided in this question;

P1 = 950 mm Hg

P2 = ?

V1 = 25 L

V2 = 30 L

T1 = 155°C = 155 + 273 = 428K

T2 = 200°C = 200 + 273 = 473K

Using P1V1/T1 = P2V2/T2

950 × 25/428 = P2 × 30/473

23750/428 = 30P2/473

55.49 = 0.063P2

P2 = 55.49 ÷ 0.063

P2 = 874.89 mmHg

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