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Setler79 [48]
3 years ago
5

Select the correct responses to the questions from the drop-down menu.

Chemistry
2 answers:
inn [45]3 years ago
6 0

Answer:

b,a

Explanation:

Damm [24]3 years ago
5 0

Answer: Fossils, Precambrian

Explanation:)

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What is the molarity of a solution that contains 0.400 mol HCl in 9.79 l solution?
Maslowich

Answer:

  • Option B, 0.0409 M

Explanation:

<u>1) Data:</u>

a) M = ?

b) n = 0.400 mol

V = 9.79 liters

<u>2) Formula:</u>

  • M = n / V (in liters)

<u>3) Solution:</u>

  • M = 0.400 mol / 9.79 liter = 0.04086 M

  • Since each data contain 3 significant digits, the answer must be reported with 3 significant digits. So, the correct answer is 0.0409 M, which is the option B.
8 0
3 years ago
According to the pattern of carbon and hydrogen atoms in alkenes, if a molecule has three carbon atoms, how many hydrogen atoms
Gekata [30.6K]
 <span>6. 

Because the general formula for alkenes is CnH2n</span>
4 0
3 years ago
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What are four chemical and physical properties of phosphorus?
DedPeter [7]

Answer:

Properties: The melting point of phosphorus (white) is 44.1°C, boiling point (white) is 280°C, specific gravity (white) is 1.82, (red) 2.20, (black) 2.25-2.69, with a valence of 3 or 5. There are four allotropic forms of phosphorus: two forms of white (or yellow), red, and black (or violet).Oct 7, 2019

Atomic Number: 15

Atomic Weight: 30.973762

Explanation:

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8 0
2 years ago
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The balanced chemical equation for the reaction of copper (Cu) and silver nitrate (AgNO3) is shown below.
lesantik [10]
Remark
The balance numbers in front of Ag and AgNO3 are both 2. That number is in moles.

Rule: if the moles are the same in the equation, then whatever you are given for one, will be the same for the other. So you have 0.854 moles of Ag. You will also have 0.854 moles of AgNO3 

Answer: 0.854 <<<<<
8 0
3 years ago
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A nitrde ion has 7protons,8nutrons and 10 electrons. what is the overall change
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the overall charge on the nitride anion is  

( 3 − ) .

N power 3 − → the nitride anion

6 0
2 years ago
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