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Luba_88 [7]
3 years ago
14

The cell reaction for a lead storage battery (car batteries, etc.) is: E° = 1.92 V. Pb(s) + PbO2(s) + 2 H+(aq) + 2HSO4-(aq)--&gt

;2PbSO4(s) + 2H2O (l) To provide a potential of around 12.6 V, how many cells would be needed?

Chemistry
1 answer:
Licemer1 [7]3 years ago
3 0

Answer:

7 cells

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

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How does a runoff get polluted.
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any litter on the ground can be swept up into the runoff. dirty ground water also commonly affects runoff since there are so many chemicals in the ground. farmers especially need to be cautious because teir fertilizers can leak into the ground.

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The chemical equation below shows the burning of magnesium (Mg) with oxygen (O2) to form magnesium oxide (MgO). 2Mg + O2 mc019-1
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3 years ago
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An acetic acid buffer solution is required to have a pH of 5.27. You have a solution that contains 0.010 mol of Acetic acid. Wha
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Answer:

Molarity of sodium acetate you will need to add is 0.0324M

Explanation:

<em>Assuming volume of the buffer is 1L.</em>

<em />

The pH of a buffer can be determined using Henderson-Hasselbalch equation:

pH = pKa + log [A⁻] / [HA]

<em>Where pKa is pKa of the weak acid,  [A⁻] molar concentration of conjugate base and [HA] molar concentration of weak acid</em>

<em />

Replacing for the acetic buffer (pKa = 4.76):

pH = 4.76 + log [Sodium Acetate] / [Acetic Acid]

As you have 0.010 moles of acetic acid in 1L:

[Acetic Acid] = 0.010mol / 1L = 0.010M

And you require a pH of 5.27:

5.27 = 4.76 + log [Sodium Acetate] / [0.010M]

0.51 = log [Sodium Acetate] / [0.010M]

10^0.51 = [Sodium Acetate] / [0.010M]

3.236 =  [Sodium Acetate] / [0.010M]

3.236 [0.010M] = [Sodium Acetate]

0.0324M = [Sodium Acetate]

<h3>Molarity of sodium acetate you will need to add is 0.0324M</h3>

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Answer:

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of 160° F. Scrambled eggs need to be cooked until firm throughout with no visible liquid egg remaining.

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